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Alex73 [517]
3 years ago
8

Julie is graduating from college. She has studied biology, chemistry, and computing and hopes to work as a forensic scientist ap

plying her science background to crime investigation. Late one night, she thinks about some jobs she has applied for. Let A, B, and C be the events that Julie is offered a job by:
A = the Connecticut Office of the Chief Medical Examiner
B = the New Jersey Division of Criminal Justice
C = the federal Disaster Mortuary Operations Response Team
Julie writes down her personal probabilities for being offered these jobs:
P(A) = 0.6
P(B) = 0.5
P(C) = 0.3
P(A and B) = 0.2
P(A and C) = 0.1
P(B and C) = 0.1
P(A and B and C) = 0
1. Make a Venn diagram of the events A, B, and C. Mark the probabilities of every intersection involving these events and their complements. Use this diagram to answer the following.
2. If Julie is offered the federal job, what is the conditional probability that she is also offered the New Jersey job? (Round your answer to two decimal places.)
3. If Julie is offered the New Jersey job, what is the conditional probability that she is also offered the federal job? (Round your answer to two decimal places.)
Mathematics
1 answer:
iren2701 [21]3 years ago
4 0

Answer:

A and B

Step-by-step explanation:

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3 years ago
Amari claims that a rectangle is sometimes a parallelogram but a parallelogram is always a
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Answer:

The statement is false.

Step-by-step explanation:

A parallelogram is a figure of four sides, such that opposite sides are parallel

A rectangle is a four-sided figure such that all internal angles are 90°

Here, the statement is:

"A rectangle is sometimes a parallelogram but a parallelogram is always a

rectangle."

Here if we found a parallelogram that is not a rectangle, then that is enough to prove that the statement is false.

The counterexample is a rhombus, which is a parallelogram that has two internal angles smaller than 90° and two internal angles larger than 90°, then this parallelogram is not a rectangle, then the statement is false.

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Anyone know how to do this??
Ghella [55]

Answer:

csc²(x)

Step-by-step explanation:

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sin²(x) + cos²(x) = 1

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cos(2x) = cos²(x) - sin²(x) = (1 - sin²(x)) - sin²(x) =

= 1 - 2×sin²(x)

=> 2×sin²(x) = 1 - cos(2x)

sin²(x) = 1/2×(1-cos(2x))

=> 1 - cos(2x) = 2×(1/2×(1-cos(2x)) = 2×sin²(x)

=> 2 / (1-cos(2x)) = 2 / (2×sin²(x)) = 1/sin²(x) =

= 1/sin(x) × 1/sin(x) = csc(x)×csc(x) = csc²(x)

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Imperial: Miles
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