Answer:
✓The type of sediment on the seafloor.
✓The type of rock on the seafloor.
✓The rate of sediment deposition.
Explanation:
Sea drilling cores are one way to get samples that can be used for analysis whereby some information such as type of sediment on the seafloor and type of rock on the seafloor can be known. Surface samplers can be collected from sediment at very top layers or inside deep of the ocean floor. These samples could have animals hidden, , water and some particles that can be analysed in the muddy deep, devices such as Coring devices can be used in collection of cores. The information that can be determined directly by analyzing seafloor drill cores are;
✓The type of sediment on the seafloor.
✓The type of rock on the seafloor.
✓The rate of sediment deposition.
The Ming emperors made it their capital in 1421 and it remained China's capital till 1912 when the Manchu Empire fell and SunYat Sen turned China into a republic.
Answer:
Sorry I dont know the answer
But anyone who dont understand the question
here it is:-
What does it depend on whether the surface represented and the information between one map and another is different?
Explanation:
Answer:
Carbonate sedimentary rocks
Explanation:
Carbonate sedimentary rocks are the rocks that are primarily comprised of carbonate minerals such as calcite or aragonite. They are formed chemically. These rocks are formed when Carbon is initially trapped with the accumulation of sediments over it in association with fossil shells. They are also formed due to the dissolution or precipitation by groundwater, depending upon the temperature, pH and dissolved ions present in the solution.
They are often marked by the presence of karst topography and caves.
Some examples of these rocks are limestone and dolomite.
Eₖ = √1/2 mv²
Eₖ/v² = 1/2 m
2Eₖ/v² = m
mgh = 1/2 mv²
gh = 1/2 v²
2gh = v²
v = √2gh
= √2 × 10 N/kg × 2 m
= 6.324 ms⁻¹
m = 9.8/(6424)²
= 9.8/39.993
= 0.245 g
I am not sure if it's correct.
i transposed for m in the first equation then to find the velocity I combined the potential and kinetic energy equation. there was no mass because velocity doesn't depend on the mass
Then I used earth's gravitational field strength (g) 10 N/kg and the 2 m was the height provided in the question
you can try working and see if you get the same
