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Anon25 [30]
3 years ago
7

Please help me fill those in please please I will give you credit please

Mathematics
1 answer:
VladimirAG [237]3 years ago
5 0

Answer:

proportional: 1, 3,5,6,8,10

non: 2,4,7,9,11,12

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Simplify the following:
Evgesh-ka [11]

First, we can bring both fractions under the common denominator (a - 3)(a - 5):

\dfrac{4}{a-3}\Big(\dfrac{a-5}{a-5}\Big) +\dfrac{9}{a-5}\Big(\dfrac{a-3}{a-3}\Big)\\\\=\dfrac{4(a-5)+9(a-3)}{(a-3)(a-5)}

Looking at the numerator, we can distribute and collect like terms:

4(a-5)+9(a-3)=4a-20+9a-27=13a-47

and looking at the denominator, we can do the same:

(a-3)(a-5)=(a-3)a+(a-3)(-5)\\=a^2-3a-5a+15\\=a^2-8a+15

With these simplified expressions, the final fraction becomes

\dfrac{13a-47}{a^2-8a+15}

6 0
4 years ago
What is the quotient of es031-1?
ArbitrLikvidat [17]

Answer:

(x - 2)

Step-by-step explanation:

Given expression is,

\frac{x^3+3x^2-4x-12}{x^2+5x+6}

We have to find the quotient.

x² + 5x + 6) x³ + 3x² - 4x - 12(x - 2

                   <u>x³ + 5x² + 6x</u>

                       -2x² - 10x - 12

                       <u>-2x² - 10x - 12</u>

                                    0

Therefore, quotient of the given expression will be (x - 2).

8 0
4 years ago
Name the marked angle in 2 different ways.
solong [7]

Answer:

∠XWV ∠UWV

Hope this helps! :)

3 0
3 years ago
Solve the system below by substitution.
Olegator [25]

Answer:

(-4, -1)

Step-by-step explanation:

6x-y=-23

Add y to both sides:

6x-y+y=-23+y\\6x=-23+y

Divide both sides by 6:

\frac{6x}{6}=-\frac{23}{6}+\frac{y}{6}\\x=\frac{-23+y}{6}

Substitute this into the second equation given:

2*\frac{-23+y}{6}+5y=-13

\frac{-23+16y}{3}=-13

Multiply both sides by 3:

-23+16y=-39

Add 23 to both sides:

-23+16y+23=-39+23\\16y=-16

Divide both sides by 16:

\frac{16y}{16}=\frac{-16}{16}\\y=-1

We know that x=\frac{-23+y}{6}.

Thus, x=\frac{-23-1}{6}

x=-4

(x, y) = (-4, -1)

6 0
3 years ago
Read 2 more answers
How do you eliminate a variable to solve an equation
Sav [38]
You can't remove a variable but you can separate the variable from the rest of the equation. If you are adding for example 64+x=88 you would subtract the 64 from 88. You will get the value of x. For anything else, you would do the opposite of whatever you are doing. Multiply if you are dividing, add if you are subtracting and hence forth. I hope this helped.
3 0
4 years ago
Read 2 more answers
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