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PilotLPTM [1.2K]
3 years ago
10

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Mathematics
1 answer:
Softa [21]3 years ago
7 0
Dhkwkgk k sad h e nah dawg he’s as Jewish
You might be interested in
The length of a human pregnancy is normally distributed with a mean of 270 days with a standard deviation of 8 days. How many da
solniwko [45]

Answer:

261.71

Step-by-step explanation:

The calculation of days is shown below:-

X = \mu + Z\sigma

where,

Mean = 270

standard deviation is 8

And, the normsinv is -1.036

Now placing these values to the above formula

So, the number of days is

= 270 + (-1.036433389)  × 8

= 270 + (-8.29146711)

= 261.708533

or

= 261.71

Therefore for computing the number of days we simply applied the above formula and for (-1.036433389) please find in the attachment.

6 0
3 years ago
Jill has a 25% off coupon for some computer software. If the coupon saved her $35, how much would the software cost without the
zysi [14]

Answer:

$140

Step-by-step explanation:

35 times 4

6 0
3 years ago
Rachel made a mosaic from different color rectangular tiles. Three tiles measured 312 inches by 3 inches. Six measured 4 inches
astraxan [27]
The answer is 10,344 hope this helps!
3 0
3 years ago
Read 2 more answers
What are the values of the variables in the triangle below? If your answer is not an integer, leave it in simplest radical form.
castortr0y [4]

Answer:

<h2>x = 12</h2><h2 /><h2>y = 4√3</h2>

Step-by-step explanation:

<u>To find x we use cosine</u>

cos∅ = adjacent / hypotenuse

x is the adjacent

8√3 is the hypotenuse

cos 30 = x / 8√3

x = 8√3 cos 30

<h3>x = 12</h3>

<u>To find y we use sine</u>

sin∅ = opposite / hypotenuse

y is the opposite

8√3 is the hypotenuse

sin 30 = y / 8√3

y = 8√3 sin 30

<h3>y = 4√3</h3>

Hope this helps you

5 0
3 years ago
Make a the subject of a2+b2=c2
wel

Answer:

a=\sqrt{c^2-b^2

⇒ a=\sqrt{(c+b)(c-b)}        [Factorized form]

Step-by-step explanation:

Given expression:

a^2+b^2=c^2

We need to make a the subject.

In order to do that we need to solve the expression for a in terms of b and c

We have,

a^2+b^2=c^2

Subtracting both sides by b^2

a^2+b^2-b^2=c^2-b^2

a^2=c^2-b^2

Taking square root both sides in order to remove square of a

\sqrt{a^2}=\sqrt{c^2-b^2}

a=\sqrt{c^2-b^2

The difference of squares can be factorized and written  as:

a=\sqrt{(c+b)(c-b)}    [difference of squares x^2-y^2=(x+y)(x-y) ]

4 0
3 years ago
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