Answer:28
Step-by-step explanation:
7+7+7+7
Answer:
The probably genotype of individual #4 if 'Aa' and individual #6 is 'aa'.
Step-by-step explanation:
In a non sex-linked, dominant trait where both parents carry and show the trait and produce children that both have and don't have the trait, they would each have a genotype of 'Aa' which would produce a likelihood of 75% of children that carry the dominant traint and 25% that don't. Since the child of #1 and #2, #5, does not exhibit the trait, nor does the significant other (#6), then they both must have the 'aa' genotype. However, since #4 displays the dominant trait received from the parents, it is more likely they would have the 'Aa' genotype as by the punnet square of 'Aa' x 'Aa', 50% of their children would have the 'Aa' phenotype.
Answer:
19 1-point shots and 32 2-point shots
Step-by-step explanation:
Let x be the amount of 1-point shots they made and y be the amount of 2-point shots they made then...
x+y=51
x+2y=83
We can solve this equation using elimination. In this case, we can eliminate x be subtracting the two equations.
-y=-32
Divide both sides by -1
y=32
Plug this back into the equation to solve for x
x+32=51
Subtract 32 from both sides
x=19
They scored 19 1-point shots and 32 2-point shots.
Answer:
23 and 13
Step-by-step explanation:
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