What does the graph for y=-3x look like
1 answer:
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This is more a biology question.
Galactosemia is an autosomal recessive genetic disease.
The probability depends on the prevalence (P) of carriers in the region.
It takes two carrier parents for a child to develop galactosemia, with probability of 1/4 because it is a recessive disease.
Therefore, under random conditions, the probability of both parents being carriers is P², and the probability that a particular child developing galactosemia is p=P²/4.
The probability of having NO (x=0) child out of n=4 developing the disease can be estimated by the binomial distribution,
P(X=x)=C(n,x)p^0(1-p)^n
which means, for p=P²/4, n=4, x=0
P(X=0)=C(4,0)p^0(1-p)^4
Consequently, the probability that at least one child will have galactosemia
P(X>0)=1-P(X=0)
From the published incidence (p) of the disease in the US estimated to be between 1/30000 to 1/60000 [ ref. nih document # PMC4413015 ], we could use p=1/45000, giving
P(X>0)
=0.0000889 (approximately)
Galactosemia is an autosomal recessive genetic disease.
The probability depends on the prevalence (P) of carriers in the region.
It takes two carrier parents for a child to develop galactosemia, with probability of 1/4 because it is a recessive disease.
Therefore, under random conditions, the probability of both parents being carriers is P², and the probability that a particular child developing galactosemia is p=P²/4.
The probability of having NO (x=0) child out of n=4 developing the disease can be estimated by the binomial distribution,
P(X=x)=C(n,x)p^0(1-p)^n
which means, for p=P²/4, n=4, x=0
P(X=0)=C(4,0)p^0(1-p)^4
Consequently, the probability that at least one child will have galactosemia
P(X>0)=1-P(X=0)
From the published incidence (p) of the disease in the US estimated to be between 1/30000 to 1/60000 [ ref. nih document # PMC4413015 ], we could use p=1/45000, giving
P(X>0)
=0.0000889 (approximately)
The shadow length of Kyle is 1.2 feet,if a lighthouse is 150 feet tall and cast a shadow of 30 feet. Kyle is standing next to a lighthouse and is 6 feet tall.
Step-by-step explanation:
The given is,
A lighthouse is 150 feet tall.
Cast a shadow of 30 feet.
Kyle is 6 feet tall.
Step:1
Ref the attachment,
From triangle ABC,
tan ∅ = ......................(1)
Where, Opp = AB = 150 feet
Adj = BC = 30 feet
Equation (1) becomes,
tan ∅ =
= 5
∅ = 5
∅ = 78.69°
∅ is same for both ABC and PQR triangle.
From triangle PQR,
tan ∅ = ......................(1)
Where, Opp = PQ = 6 feet
Adj = QR = x
Equation (1) becomes,
tan 78.96° =
5 =
x = = 1.2
Shadow length of Kyle, x = 1.2 feet
Result:
The shadow length of Kyle is 1.2 feet, if a lighthouse is 150 feet tall and cast a shadow of 30 feet. Kyle is standing next to a lighthouse and is 6 feet tall.
