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3 years ago

Describe the relationship between the graph

Mathematics

1 answer:

MAVERICK [17]3 years ago

4 0

Option D
4 is a horizontal shift to right four units and 3 is the vertical translation 3 units up

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Silva set up a dog-walking buisness. He earned $60 in June. He is projected to earn 110% more in July. How much is Silvia projec

Jlenok [28]

I think that gain of Silva, in July, is: 60+110100∗60=60+1110∗60=60+66=126$
so A.

6 0

3 years ago

Read 2 more answers

Please help me I think the answer is 12 cm .

-Dominant- [34]

You can find the value of the hypotenuse if you apply the Pythagorean Theorem, which is show below:

h²=a²+ b² ⇒ h=√(a² + b²)

h: hypotenuse (the opposite side of the right angle and the longest side of the triangle).

a and b: legs (the sides that form the right angle).

Then, you have:

h²=a² + b²

h²=12²+12²

h=√ ((12)² + (12)²)

h=12√2

What is the lenght of the hypotenuse?

The answer is: The length of the hypotenuse is 12√2

6 0

3 years ago

Can someone help wit this just find the value of x

Romashka-Z-Leto [24]

2x-2+x+5=90
3x+3=90
-3 -3
3x/3 =87/3
x=29

6 0

3 years ago

Create a linear function that has a rate of change of -4 and a solution at (-5,2)

san4es73 [151]

You would use the point-slope equation of y-y₁=mx(x-x₁)

So the rate of change is the slope and equals m, so m=-4

and has a solution at (-5,2) which would be the (x₁, y₁) and then it is just plugging in the numbers

y - (2) = (-4)(x - (-5))

y - 2 = -4 (x+5)

y - 2 = -4x - 20

y = -4x - 18

8 0

3 years ago

Without using a trigonometric ratio, find the distance from the ship to the buoy, B. Round the distance to the nearest tenth of

alexdok [17]

Without using the trigonometry ratio, we can find the distance between the ship and the buoy by:

the distance between City and Lemont SUBTRACT the vertical distance between City and the point parallel to the Ship

The distance between the City and Lemont can be worked out using the Sin rule
$\frac{57.8}{sin(36)}= \frac{City-Lemont}{sin(92)}$
$City-Lemont= \frac{57.9sin(92)}{sin(36)} = 98.27.....$ ≈98.3

The vertical distance between the City and the point parallel to the ship can be worked out using the Pythagoras theorem
$\sqrt{57.8^{2}- 44.6^{2} } =36.765...$ ≈36.8

The distance between the ship and the Buoy is given:
$98.3-36.8=61.5$ miles

5 0

3 years ago