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vodka [1.7K]
3 years ago
8

James determined that these two expressions were equivalent expressions using the values of x = 4 and x = 6. Which statements ar

e true? Check all that apply.
Ο 7 x + 4 and 3 x + 5 + 4 x - 1 When x = 2, both expressions have a value of 18.
Ο The expressions are only equivalent for x = 4 and x = 6.
Ο The expressions are only equivalent when evaluated with even values.
Ο The expressions have equivalent values for any value of x.
Ο The expressions should have been evaluated with one odd value and one even value.
Ο When x = 0, the first expression has a value of 4 and the second expression has a value of 5.
Ο The expressions have equivalent values if x = 8
Mathematics
1 answer:
rodikova [14]3 years ago
8 0

Answer:

Ο 7 x + 4 and 3 x + 5 + 4 x - 1 When x = 2, both expressions have a value of 18.

Ο The expressions are only equivalent when evaluated with even values.

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Money Flow  The rate of a continuous money flow starts at $1000 and increases exponentially at 5% per year for 4 years. Find the
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Answer:

Present value =  $4,122.4

Accumulated amount = $4,742

Step-by-step explanation:

Data provided in the question:

Amount at the Start of money flow = $1,000

Increase in amount is exponentially at the rate of 5% per year

Time = 4 years

Interest rate = 3.5%  compounded continuously

Now,

Accumulated Value of the money flow = 1000e^{0.05t}

The present value of the money flow = \int\limits^4_0 {1000e^{0.05t}(e^{-0.035t})} \, dt

= 1000\int\limits^4_0 {e^{0.015t}} \, dt

= 1000\left [\frac{e^{0.015t}}{0.015} \right ]_0^4

= 1000\times\left [\frac{e^{0.015(4)}}{0.015} -\frac{e^{0.015(0)}}{0.015} \right]

= 1000 × [70.7891 - 66.6667]

= $4,122.4

Accumulated interest = e^{rt}\int\limits^4_0 {1000e^{0.05t}(e^{-0.035t}} \, dt

= e^{0.035\times4}\times4,122.4

= $4,742

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Your friend says that it is impossible for the circumcenter of a triangle to
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How many times dose 109 go into 4
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