Answer:
1.) There are 16 juniors and 8 seniors in the Chess Club. If the club members decide to send 9 juniors to a tournament, how many different possibilities are there?
(16 over 9) = 16!/(9!*7!) = 11440
2.) How many different ways can 3 cards be drawn from a deck of 52 cards without replacement?
52*51*50 = 132600
3.) How many different ways can 3 cards be drawn from a deck of 52 cards with replacement?
52^3 = 140608
4.) A corporation has 5 officers to choose from which 3 are selected to comprise the board of directors. How many combinations are there?
(5 over 3) = 5!/(3! * 2!) = 10
5.) A combination lock has the numbers 1 to 40 on each of three consecutive tumblers. What is the probability of opening the lock in ten tries?
10/40^3 = 1/6400
<span> 25 30 35 40 46 60.5 75 80 81 82 90
min Q1 Q2/med Q3 max
81-35=46=Interquartile range
</span><span>Is that all the information you wanted?</span>
20(5)-8(2)+3(2-5)+5
100-16-9= 79
Answer:
Multiply the top equation by 3
Step-by-step explanation:
So plug in 10 for r which would give you 3(10)=10+5s the multiply 3x10 so you should have 30=10+5s you want to get 5s by its self to subtract 10 to both sides so you should get 20=5s them divide 5 to both sides and you get s=4
