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Tom [10]
3 years ago
15

NEED HELP WITH THIS PLEASE. NEED THE ANSWER ASAP

Mathematics
1 answer:
padilas [110]3 years ago
7 0

Answer:

PY = 8

Step-by-step explanation:

Lets run down the other three to show why they're wrong

<em>MY=8</em>

By P.T, that's wrong (PERPENDICULAR)

<em>PM=MY </em>

We can't prove that with the given

XY=42

Again, by P.T., this is false

BTW: You can prove PY=8 by proving XMP congruent to YMP by SAS

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Find the area?<br> Show work
Ivenika [448]

Answer:

294 square units

Step-by-step explanation:

35^2-21^2=a^2

a^2=784

square root 784=28

21*28/2=294

Answer=294

4 0
3 years ago
How many hours is 10 miles?
Aleksandr-060686 [28]
Depends on the speed
7 0
3 years ago
Heights of men have a bell-shaped distribution, with a mean of 176 cm and a standard deviation of 7 cm. Using the Empirical Rule
Vaselesa [24]

Answer:

a) 68% of the men fall between 169 cm and 183 cm of height.

b) 95% of the men will fall between 162 cm and 190 cm.

c) It is unusual for a man to be more than 197 cm tall.

Step-by-step explanation:

The 68-95-99.5 empirical rule can be used to solve this problem.

This values correspond to the percentage of data that falls within in a band around the mean with two, four and six standard deviations of width.

<em>a) What is the approximate percentage of men between 169 and 183 cm? </em>

To calculate this in an empirical way, we compare the values of this interval with the mean and the standard deviation and can be seen that this interval is one-standard deviation around the mean:

\mu-\sigma=176-7=169\\\mu+\sigma=176+7=183

Empirically, for bell-shaped distributions and approximately normal, it can be said that 68% of the men fall between 169 cm and 183 cm of height.

<em>b) Between which 2 heights would 95% of men fall?</em>

This corresponds to ±2 standard deviations off the mean.

\mu-2\sigma=176-2*7=162\\\\\mu+2\sigma=176+2*7=190

95% of the men will fall between 162 cm and 190 cm.

<em>c) Is it unusual for a man to be more than 197 cm tall?</em>

The number of standard deviations of distance from the mean is

n=(197-176)/7=3

The percentage that lies outside 3 sigmas is 0.5%, so only 0.25% is expected to be 197 cm.

It can be said that is unusual for a man to be more than 197 cm tall.

3 0
3 years ago
75 pins of juice in 5 containers find the rate and unit rate
Eva8 [605]

Answer: 15 juice pins per container

75 Juice pins ÷ 5

5 Containers ÷ 5

=

15 Juice pins

1 Container

=

15 Juice pins

1 Container

= 15 Juice pins per Container


4 0
3 years ago
Miss logan leaves school at 15:55 it takes her 1 hour and 20 mins to get home what time does she arrive home? answer using 24 ho
cluponka [151]

Answer:

5:15

Step-by-step explanation:

15:55 = 3:55 in normal time

3:55 + 1 hr = 4:55

4:55 + 20 min = 5:15

6 0
3 years ago
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