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Troyanec [42]
3 years ago
5

Se necesita cercar un terreno de forma rectangular con alambre que cuesta $7,20 el metro. Si el terreno tiene 125m² y el largo e

s el doble que el ancho. ¿cuánto alambre se necesita?
Mathematics
1 answer:
il63 [147K]3 years ago
4 0

Answer:

La cantidad de cable necesaria es de 47.43 metros.

Step-by-step explanation:

La información dada es;

Longitud, L de la tierra = 2 × Ancho, W de la tierra

Por lo tanto tenemos;

L = 2 × W

El área cubierta por la tierra = 125 m²

Lo que da;

L × W = 125 m² = 2 × W × W = 2 × W²

W² = 125/2 = 62.5

W = √62.5 = \frac{5}{2} \sqrt{10} = 7,91 metros

La longitud = 2 × ancho = 2 ×  \frac{5}{2} \sqrt{10} = 5·√10 metros

La longitud del cable requerido = El perímetro de un rectángulo que forma la cerca = 2 × Ancho + 2 × Longitud del rectángulo

 La longitud del cable requerido = 2 × 5·√10 + 2× \frac{5}{2} \sqrt{10} = 10 · √10 + 5 · √10 = 15 · √10 metros = 47.43 metros.

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