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LUCKY_DIMON [66]
3 years ago
12

Please help me this is due soon!! ill mark brainiest :)) i also need a reason why please!!

Mathematics
1 answer:
N76 [4]3 years ago
5 0

Answer:

b

Step-by-step explanation:

One square = (2/5)/(3) Invert and multiply the 3

2      1

==    ==    =

5       3

2/15

5 squares = 5 * 2/15 = 10 / 15 = 2/3

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Answer:

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List 0.5 1/5 0.35 12/25 4/5 from least to greatest
Anika [276]
One way is to make them all decimals or all fractions:

.5   .2  .35  .48  .80  are the numbers above changed to decimals.
I will make them the same length (two digit past the decimal point) to compare
.50   .20  .35  .48 and .80

Now it is easy to put them in order

.2  .35  .48   .5  and .80

Let's put them into all fractions

5/10   1/5   35/100   12/25 and 4/5

Instead of finding a common denominator let's try this:
Think of them as test scores - the person who got 1 out 5 did the worst
Next came the person who got only 35 out of 100 - they only did better than the one above (1/5)
12/25 is almost 1/2 but a little below half the questions right
5/10 is exactly half the questions right (so it is bigger than 12/25 by a little).
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So 1/5, 35/100, 12/25, .5 and 4/5 are in order least to greatest and match the answer above in bold.
3 0
3 years ago
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Bethany has 43 apples.write a subtraction story about the apples that would require regrouping.
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A colony of bacteria is growing at a rate of 0.2 times its mass. Here time is measured in hours and mass in grams. The mass of t
11Alexandr11 [23.1K]

Answer:

  • <u>Question 1:</u>      dm/dt=0.2m<u />

<u />

  • <u>Question 2:</u>     m=Ae^{(0.2t)}<u />

<u />

  • <u>Question 3:</u>      m=10e^{(0.2t)}<u />

<u />

  • <u>Question 4:</u>      m=10g<u />

Explanation:

<u>Question 1: Write down the differential equation the mass of the bacteria, m, satisfies: m′= .2m</u>

<u></u>

a) By definition:  m'=dm/dt

b)  Given:  rate=0.2m

c) By substitution:  dm/dt=0.2m

<u>Question 2: Find the general solution of this equation. Use A as a constant of integration.</u>

a) <u>Separate variables</u>

     dm/m=0.2dt

b)<u> Integrate</u>

           \int dm/m=\int 0.2dt

            ln(m)=0.2t+C

c) <u>Antilogarithm</u>

       m=e^{0.2t+C}

       m=e^{0.2t}\cdot e^C

         e^C=A\\\\m=Ae^{(0.2t)}

<u>Question 3. Which particular solution matches the additional information?</u>

<u></u>

Use the measured rate of 4 grams per hour after 3 hours

            t=3hours,dm/dt=4g/h

First, find the mass at t = 3 hours

            dm/dt=0.2m\\\\4=0.2m\\\\m=4/0.2\\\\m=20g

Now substitute in the general solution of the differential equation, to find A:

          m=Ae^{(0.2t)}\\\\20=Ae^{(0.2\times 3)}\\\\A=20/e^{(0.6)}\\\\A=10.976

Round A to 1 significant figure:

  • A = 10.

<u>Particular solution:</u>

           

             m=10e^{(0.2t)}

<u>Question 4. What was the mass of the bacteria at time =0?</u>

Substitute t = 0 in the equation of the particular solution:

         m=10e^{0}\\\\m=10g

3 0
3 years ago
Given that a = 10,
tankabanditka [31]

Since a = 10 and b = 2x + 5, we have

ab=10(2x+5)=20x+50

So, the equation becomes

ab = 6x^2 +11x-10 \iff 20x+50= 6x^2 +11x-10 \iff 6x^2-9x-60=0

The solutions to this equation are 4 and -5/2, so I'm afraid there's a typo in your question.

3 0
3 years ago
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