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Irina-Kira [14]
3 years ago
12

Pleases help (: Simplify the expression below √256

Mathematics
1 answer:
Ad libitum [116K]3 years ago
4 0

\sqrt{256} = \sqrt{2^8} = 2^4 = 16

Answer: 16

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Solve the equation: Sin2x - Sinx = 0
Viktor [21]
We know that sin2x=2sinxcosx 
(search the net for proof if you wish) 

So the original equation becomes

2sinxcosx-sinx=0
The two terms both have sinx that can be taken out to get: 

sinx(2cosx-1)=0 
This is true if sinx=0 or 2cosx-1=0 , rewritten: cosx=1/2

sinx=0 than x=2kπ
cosx=1/2 than x=π/3+2kπ
where k is an integer

5 0
4 years ago
Differences in linear and quadratic equations
BabaBlast [244]

Answer:

linear equation has two variables doesn't involve any power

quadratic equation involves one of the variables raised to the second power.

Step-by-step explanation:

A <u>linear equation</u> in two variables doesn't involve any power higher than one for either variable. It has the general form Ax + By + C = 0, where A, B and C are constants. ... A <u>quadratic equation</u>, on the other hand, involves one of the variables raised to the second power.

7 0
3 years ago
Can someone help me with this question?
zysi [14]

The reflection over the y-axis has a rule:

(x,y)\rightarrow (-x,y).

From the diagram you can see that point W has coordinates (-7,2). Then using the rule given above, you can find the coordinates of point W':

(-7,2)\rightarrow (7,2).

Answer: (7,2).

8 0
4 years ago
Read 2 more answers
1. The beginning steps for determining the center and radius of a circle using the completing the square method are shown below:
svet-max [94.6K]

(1) Answer : (x^2 - 6x + 9) + (y^2- 4y + 4) = 3 + (9 + 4)

Step 1: x^2 - 6x + y^2 - 4y = 3

Step 2: (x^2- 6x) + (y^2 - 4y) = 3

In completing the square method we take coefficient of x and divide by 2 and the square it . Then add it on both sides

The coefficient of x is -6. \frac{-6}{2} = (-3)^2 = 9

The coefficient of y is -4. \frac{-4}{2} = (-2)^2 = 4

Step : (x^2- 6x + 9) + (y^2 - 4y + 4) = 3 +9 + 4

(2) x^2 +  y^2 +  6x - 6y + 2 = 0

To find center and radius we write the equation in the form of

(x-h)^2 + (y-k)^2 = r^2 using completing the square form

Where (h,k) is the center and 'r' is the radius

x^2 +  y^2 +  6x - 6y + 2 = 0

(x^2 +  6x) +  (y^2  - 6y) + 2 = 0

In completing the square method we take coefficient of x and divide by 2 and the square it . Then add it on both sides

(x^2 +  6x + 9) +  (y^2  - 6y + 9)  = -2 + 9 + 9

(x + 3)^2 +  (x - 3)^2 = 16

Here h= -3 and k=3 and r^2 = 16 so r= 4

Center is (-3,3) and radius = 4

(c) Step 1: x^2 + 8x + y^2 -  6y = 11

Step 2: (x^2 + 8x) + (y^2 -  6y) = 11

Step 3: (x^2 + 8x + 16) + (y^2 - 6y + 9) = 11 + (16 + 9)

Step 4: (x^2 + 8x + 16) + (y^2 - 6y + 9) = 36

We factor out each quadratic

(x^2 + 8x + 16) = (x+4)(x+4) = (x+4)^2

((y^2 - 6y + 9)) = (x-3)(x-3) = (x-3)^2

Step 5 :(x + 4)^2 + (y - 3)^2 = 6^2

5 0
3 years ago
What is t if 5/7t = 15
Black_prince [1.1K]

Answer:

21

Step-by-step explanation:

15/ 5/7 = 21

8 0
4 years ago
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