Answer:
C. H(x) = 2x+6
Step-by-step explanation:
Volume of the cylindrical silo = Area of its circular base × Height
Volume of the cylindrical silo = πr²×H
If the area of the circular base of the silo is given by the function A(x), the volume is given by C(x) and the height is given by H(x), the formula can be expressed as;
C(x) = A(x) × H(x)
The height of the cylindrical silo will be;
H(x) = C(x)/A(x)
Given C(x) = 6.28x³ + 18.84x² and
A(x) = 3.14x²
H(x) = 6.28x³ + 18.84x²/3.14x²
H(x) = x²(6.28x+18.84)/3.14x²
H(x) = (6.28x+18.84)/3.14
H(x) = 3.14(2x+6)/3.14
H(x) = 2x+6
Hence, the function, H(x) that represents the height of the silo is 2x+6.
x is called the domain of the problem.
I hope this helps.
please make me brainliest.♥
Answer:
-x^2 - 3
Step-by-step explanation:
SO we know f(x); x^2
when you place a (-), it flips teh image across the x-axis.
Finally, we see that the line is at (0,-3). To get it there, we need to go down 3, which gives us the -3 in the equation.
So we have -x^2-3
(rember the - sign is to flip it across the x-axis, and the -3 is to move the line 3 down the y-axis)
I checked my answer on a calculator btw lol.
$27.50 you would just multiply 2.75 by 10
