The sum of four consecutive multiples of 4 is 72 . Find the numbers.

Mathematics

2 answers:

Oxana [17]3 years ago

8 0

Answer:

34 and 38

Step-by-step explanation:

netineya [11]3 years ago

7 0

The answer is 34 and 38

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Please help with this

pochemuha

The problem is not well-specified. You can write a check, use a credit or debit card, or use an electronic payment app to avoid any use of cash whatever.

You can pay with 26 quarters and tell the seller to "keep the change." Again, no dollar bills, dimes, or pennies are involved.

If you pay with cash using the highest possible denominations, you can use the following complement of bills and coins to minimize the number of dollars, dimes, and pennies:
1 × $5
1 × $1
1 × 25¢
2 × 10¢ . . . (or substitute 4 × 5¢ to use no dimes)
4 × 1¢

5 0

4 years ago

Caden states that n^2 +3n + 2n is an equivalent expression to 6n. Why is Caden's statement incorrect?

malfutka [58]

$\begin{gathered} \text{The simplification of n}^2+3n+2n\text{ is:} \\ i)n^2+5n \\ By\text{ collecting common term, this can be written in form of:} \\ ii)\text{ n(n+5)} \end{gathered}$

Thus, options A and D hold, from the simplifications above.

Let's consider the validity of the remaining options provided.

$\begin{gathered} \text{For option B)} \\ \text{substitute for n=1 into the expression n}^2+3n+2n,\text{ we have} \\ 1^2+3(1)+2(1)=1+3+2=6 \\ \text{substitute for n=1 into the expression 6n, we have} \\ 6(1)=6 \\ \text{Thus, the expression n}^2+3n+2n\text{ is equivalent to 6n, for n=1} \end{gathered}$ $\begin{gathered} \text{For option C)} \\ \text{The expression n}^2+3n+2n\text{ does not simplify to 7n} \end{gathered}$ $\begin{gathered} \text{For option E)} \\ \text{substitute for n=4 into the expression n}^2+3n+2n,\text{ we have:} \\ 4^2+3(4)+2(4)=16+12+8=36 \\ \text{substitute for n=6 into the expression 6n, we have:} \\ 6(4)=24 \\ \text{Thus, the two(2) expressions are not equivalent to each other, for n=4} \end{gathered}$ $\begin{gathered} \text{For option F)} \\ \text{substitute for n=3 into the expression n}^2+3n+2n,\text{ we have:} \\ 3^2+3(3)+2(3)=9+9+6=24 \\ \text{substitute for n=3 into the expression 6n, we have:} \\ 6(3)=18 \\ \text{Thus, the two(2) expressions are not equivalent to each other, for n=3} \end{gathered}$

Hence, the correct options that apply are options A, D, E and F

7 0

1 year ago

1. Evaluate the function f(x)=3x-1 using the domain of -2, 0, 3, and 5. Results are to be shown in a table.

IceJOKER [234]

Answer:

See explanation

Step-by-step explanation:

You are given the function $f(x)=3x-1$

The domain of the function are all possible values of variable x, so you can find f(x) for x=-2, 0, 3, 5:

$f(-2)=3\cdot (-2)-1=-6-1=-7\\ \\f(0)=3\cdot 0-1=0-1=-1\\ \\f(3)=3\cdot 3-1=9-1=8\\ \\f(5)=3\cdot 5-1=15-1=14$

The table is

$\begin{array}{cc}x&f(x)\\-2&-7\\0&-1\\3&8\\5&14\end{array}$

The inverse function $f^{-1}(x)$ has the domain which is the range of the function f(x) (all possible values of f(x)), so the domain of inverse function is {-7,-1,8,14}