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2 years ago

What is (4-x^2)(4-x^2) ?

Mathematics

1 answer:

Studentka2010 [4]2 years ago

4 0

Answer:

x^4 - 8 x^2 + 16

Step-by-step explanation:

Use formula (a-b)^2 = a^2-2ab+b^2

now a=4 b=x^2, plug in

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(SAT Prep) Find the value of x.

emmainna [20.7K]

Answer:

120 deg

Step-by-step explanation:

Draw a horizontal line that passes vertices of 2 angles 125 deg and 115 deg.

This line is perpendicular with 2 vectors.

Apply the property of vertical angles and the sum of 3 angles in a triangle.

x = 180 - (125 - 90) - (115 - 90) = 120 deg

5 0

2 years ago

First question, thanks. I believe there should be 3 answers

zysi [14]

Given: The following functions

$A)cos^2\theta=sin^2\theta-1$ $B)sin\theta=\frac{1}{csc\theta}$ $\begin{gathered} C)sec\theta=\frac{1}{cot\theta} \\ D)cot\theta=\frac{cos\theta}{sin\theta} \\ E)1+cot^2\theta=csc^2\theta \end{gathered}$

To Determine: The trigonometry identities given in the functions

Solution

Verify each of the given function

$\begin{gathered} cos^2\theta=sin^2\theta-1 \\ Note\text{ that} \\ sin^2\theta+cos^2\theta=1 \\ cos^2\theta=1-sin^2\theta \\ Therefore \\ cos^2\theta sin^2\theta-1,NOT\text{ }IDENTITIES \end{gathered}$

$\begin{gathered} sin\theta=\frac{1}{csc\theta} \\ Note\text{ that} \\ csc\theta=\frac{1}{sin\theta} \\ sin\theta\times csc\theta=1 \\ sin\theta=\frac{1}{csc\theta} \\ Therefore \\ sin\theta=\frac{1}{csc\theta},is\text{ an identities} \end{gathered}$

$\begin{gathered} sec\theta=\frac{1}{cot\theta} \\ note\text{ that} \\ cot\theta=\frac{1}{tan\theta} \\ tan\theta cot\theta=1 \\ tan\theta=\frac{1}{cot\theta} \\ Therefore, \\ sec\theta\ne\frac{1}{cot\theta},NOT\text{ IDENTITY} \end{gathered}$

$\begin{gathered} cot\theta=\frac{cos\theta}{sin\theta} \\ Note\text{ that} \\ cot\theta=\frac{1}{tan\theta} \\ cot\theta=1\div tan\theta \\ tan\theta=\frac{sin\theta}{cos\theta} \\ So, \\ cot\theta=1\div\frac{sin\theta}{cos\theta} \\ cot\theta=1\times\frac{cos\theta}{sin\theta} \\ cot\theta=\frac{cos\theta}{sin\theta} \\ Therefore \\ cot\theta=\frac{cos\theta}{sin\theta},is\text{ an Identity} \end{gathered}$

$\begin{gathered} 1+cot^2\theta=csc^2\theta \\ csc^2\theta-cot^2\theta=1 \\ csc^2\theta=\frac{1}{sin^2\theta} \\ cot^2\theta=\frac{cos^2\theta}{sin^2\theta} \\ So, \\ \frac{1}{sin^2\theta}-\frac{cos^2\theta}{sin^2\theta} \\ \frac{1-cos^2\theta}{sin^2\theta} \\ Note, \\ cos^2\theta+sin^2\theta=1 \\ sin^2\theta=1-cos^2\theta \\ So, \\ \frac{1-cos^2\theta}{sin^2\theta}=\frac{sin^2\theta}{sin^2\theta}=1 \\ Therefore \\ 1+cot^2\theta=csc^2\theta,\text{ is an Identity} \end{gathered}$

Hence, the following are identities

$\begin{gathered} B)sin\theta=\frac{1}{csc\theta} \\ D)cot\theta=\frac{cos\theta}{sin\theta} \\ E)1+cot^2\theta=csc^2\theta \end{gathered}$

The marked are the trigonometric identities

3 0

11 months ago

Tarea: Expresiones Algebraicas Instrucciones: Evalúa las siguientes expresiones algebraicas con la información dada. Recuerda in

Ainat [17]

Answer:

-23.3

Step-by-step explanation:

Given:

a = 3, b = -2, c = 5. 1

Equation;

2a + 3b - 3c + 4b

Find:

Solution

Computation:

2a + 3b - 3c + 4b

2(3) + 3(-2) - 3(5.1) + 4(-2)

6 - 6 - 15.3 - 8

-23.3

7 0

2 years ago

M: 3/2, (4, 6)<br> In point-slope from

omeli [17]

Answer:

y - 4= 3/2 (x-4)

Step-by-step explanation:

4 0

2 years ago

Which of the following are characteristics of the graph of the absolute value parent function?

lora16 [44]

The graph of an absolute value parent function is a pair of rays in quadrant 1 & 2, as shown in the graph.

The absolute value function is

f(x) = |x| or y = |x|

We also know that the absolute function can be wriiten as

y = |x|

=> y = x or y = -x

Comparing with y = mx + c

We get

m = 1 or m=-1 and c = 0

c = 0 implies that the line passes through the origin.

Hence the slopes shall be -1, 1 & the line passes through the origin.

Option A, B & D are the right answers.

7 0

2 years ago

Read 2 more answers