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Virty [35]
3 years ago
6

A triangle has two side lengths of 7 and 12. what value could the length of the third side be?

Mathematics
2 answers:
Zolol [24]3 years ago
8 0
7x12 =52 so that is your answer 52
erik [133]3 years ago
6 0

Answer:

13.9

Step-by-step explanation:

7^2 + 12^2 = c^2

49 + 144 = 193

square root 193

and it’s 13.9

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Evaluate f(x)= 1.8 X 2^x for x=6 <br><br> A: 115.2<br><br> B: 2176.78<br><br> C: 21.6
attashe74 [19]
By substitution
f(6) = 1.8×2^(6)
= 1.8×64
= 115.2
3 0
3 years ago
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A bacteria culture starts with 100 bacteria and doubles in size every half hour.
taurus [48]

Answer:

y=25600

y=100(2)^{2t}

y=252

Step-by-step explanation:

A bacteria culture starts with 100 bacteria and doubles in size every half hour.

y=100(2)^{2x}

where x represents the number of hours

(a) t= 4 hours

Plug in 4 for t  and find out the number of bacteria y

y=100(2)^{2 \cdot 4}\\y=25600

25600 bacteria

y=100(2)^{2t}

convert 40 seconds into hour

40 divide by 60 =2/3

y=100(2)^{2\frac{2}{3} }\\y=100(2)^{\frac{4}{3} }\\\\y=252

The graph is attached below

4 0
2 years ago
What is the measure of angle x? need help asap <br>​
Blizzard [7]

Answer:

83! :)

Step-by-step explanation:

It all equals 180.

So,

53+44+?=180

180-53-44=83! :)

83+53+44=180! :)

7 0
3 years ago
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Determine the current through each of the LEDs in the circuits below. Which LED will be
Anika [276]

a. I = 6. 1 × 10^-4 A

b. I = 2. 6 × 10^-3 A

c. I = 0. 04 A

The LED which would glow brightest is LED C with the greatest current and voltage

The LED which would be the most dim is LED B with low voltage and consequently low current.

<h3>How to determine the current</h3>

The formula for finding current

I = V/R

Where v = voltage

R = resistance

A. V = 12V

R = 4. 7 + 15 = 19. 7 kΩ = 19700 Ω in series

I = \frac{12}{19700}

I = 6. 1 × 10^-4 A

B. V = 9V

R = 4. 7 + 1 = 4. 7 kΩ = 4700Ω in series

I = \frac{12}{4700}

I = 2. 6 × 10^-3 A

C.  V=  12V

1/R = \frac{1}{750} + \frac{1}{1200} + \frac{1}{950 } = 3. 22 × 10^-3

R = \frac{1}{3. 22 * 10 ^-3} = 310. 56 Ω

I = \frac{12}{310. 56}

I = 0. 04 A

It is important to note that the brightness of a bulb depends on both current and voltage depending on whether the bulb it is in parallel or series.

The LED which would glow brightest is LED C with the greatest current and voltage

The LED which would be the most dim is LED B with low voltage and consequently low current.

Learn more about Ohms law here:

brainly.com/question/14296509

#SPJ1

8 0
1 year ago
What is 6 1/8 minus 2 1/12
Bezzdna [24]

Answer:

4 1/24

Step-by-step explanation:

4 0
3 years ago
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