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Reptile [31]
3 years ago
7

SERIOULSLY WOULD SOMEONE JUST HELP ME WITH THESE QUESTIONS FOR ONCE? BY THAT I MEAN NOT ONLY ANSWER 23 AND 22 ALSO 24, 25, 26,27

,28,29, AND 30 AND GIVE ME SOME PROPER ANSWERS. PLEASE ASAP I have other stuff to do you know not only this so that's why I need it done as possible
​

Mathematics
1 answer:
Fantom [35]3 years ago
4 0

Answer:

Step-by-step explanation:

22. √125 is closer to √121 or 11

23. √23.5 is closer to √25 or 5

24. ∛59 is closer to ∛64 or 4 (cubed)

(4 cubed = 64, 3 cubed = 27)

25. ∛430 is closer to ∛512 or 8

(512 - 430 = 82

430- 343= 87)

26. y² = 55 is equal to y = √55,  Closer to √49 or 7

27. d² = 95 is equal to d = √95, Closer to √100 or 10

28. p² = 6.8 is equal to p = √6.8, Closer to √9 or 3

29. ∛210 is closer to ∛216 or 6 (cubed)

30. ∛520 is closer to ∛512 or 8 (cubed)

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Graph of y=(x-3)(x+4)
tekilochka [14]

Answer:

For graph refer to attachment .

Step-by-step explanation:

We need to plot the graph of a given function . The given function is ,

\rm\implies y = ( x - 3)(x+4)

When we will simplify the RHS term we will get ,

\rm\implies y = x( x + 4 ) -3(x + 4 )

Simpify the brackets ,

\rm\implies y = x^2 + 4x -3x -12

Add like terms , we have ,

\rm\implies \boxed{\blue{\rm y = x^2+x -12}}

<u>From </u><u>the</u><u> </u><u>equation</u><u> </u><u>:</u><u>-</u><u> </u>

  • The graph will cut x axis at 3 and -4 as x = 3 and -4 are the roots of the equation .
  • The graph will cut y axis at (0,-12)
  • The vertex of the graph will be (-0.5,-12.5)

<u>For the graph refer to attachment .</u>

5 0
3 years ago
Identify the property being demonstrated for each expression.
Sidana [21]

Answer:

3 + (5 + 7) = (3 + 5) + 7

Associative property

(3){5(7)} = (3){7(5)}

Commutative Property

5 + 0 = 5

Identity Property

Step-by-step explanation:

5 0
3 years ago
Write out each step of the 3-step test for continuity for the following functions at the given point. If the function is discont
balandron [24]

If we simply substitute the value x=2 in the expression we have

f(2) = \dfrac{4-12+8}{4-2-2} = \dfrac{0}{0}

which is undefined.

But if we factor both numerator and denominator, we have

f(x)=\dfrac{x^2-6x+8}{x^2-x-2} = \dfrac{(x-2)(x-4)}{(x+1)(x-2)}

Since we are studying the limit as x approaches 2, we can assume that x is not 2. In this case, we can simplify the (x-2) parenthesis, and the expression becomes

f(x)=\dfrac{x-4}{x+1}

And we can evaluate this at 2 with no problems:

f(2) = \dfrac{2-4}{2+1} = -\dfrac{2}{3}

So, we have

\displaystyle \lim_{x\to 2}f(x) = -\dfrac{2}{3}

This means that in this case both left and right limits exist and are the same, so the limit exists, but the function is not defined at x=2. This is a removable discontinuity, because we can define the function as its limit, and we have a continuous function at x=2:

f(x) = \begin{cases}\dfrac{x^2-6x+8}{x^2-x-2} &\text{if }x \neq 2\\ -\frac{2}{3} &\text{if }x = 2\end{cases}

8 0
4 years ago
When two pipes fill a pool together, they can finish in 5 hours. If one of the pipes fills half the pool then the other takes ov
Alexxandr [17]

♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫

➷The answer is 18 hours.

Explanation: If you look carefully, you can see that the answer is the second condition as well. If one pipe did half, then the other pipe took over and that took 18 hours, that means that it equals one pipe filling the pool continuously by itself. :)

✽

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

DOGE

3 0
4 years ago
: 88, 87, 89 90, 87, 85, 88, 91, 86, 86, 88, 89<br>what's is the inerquartile range​
andreyandreev [35.5K]
I think 88 i don’t really know
8 0
3 years ago
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