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A passenger flies on a heading of N40W with an airspeed of 240 km/h. His actual ground velocity is 250 km/h at a bearing of N60E. the speed and direction of the wind are V=245.15kw/h at N83.46E. This is further explained below.
<h3>What is the speed and direction of the wind.?</h3>Generally, the equation for the cosine rule is mathematically given as
a2 = b2 + c2 – 2bc cos ∠x.
Therefore
V^2 = (240^2 + 250^2) – (2(240*250)* cos 100)
V^2=140937.7813
V=375.42kw/h
In conclusion, the sine rule is mathematically given as
Sin x/240=sin60/375.42kw/h
Therefore
sin x=sin100*250/375.42kw/h
x=40.981
Hence
Direction N83.46E
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