Answer : p=2
2p-2-5x=-2(7-2x)
First, work on the parentheses. So the -2 on the outside as to be multiplied by the 7 , which gets -14 . Then you multiply the -2 by the 2x, which is 4x.
It will go from -2(7-2x) to -14+4x
But if the -14+4x looks too confusing, you can just switch them around to look “normal”. So it would be 4x-14 .
Now that we’re finished with one side of the problem, we’ll go to the other side.
On the left side , there are two variables, or letters. Because they are the same letter (p) all you have to do is add them together.
3p
-5p
+—-
-2p
And then just carry the -2 that was originally there , so it’s -2p-2
Now the equation is
-2p-2 = 4p-14
So we’re going to add 2p to both sides.
The -2p on the left cancels out, and the 4p on the right side becomes 6p
-2 = 6p-14
Next, you are going to want to isolate the variable. (Leave the letter by itself) so you add 14 to the -14 , so it can cancel out. (AND DO THE SAME ON THE OTHER SIDE)
So, you add 14 to the -2 on the left of the equation. Which comes out to 12.
12 = 6p
Lastly, divide the 6p , so you can get the letter on it’s own. And do the same on the other side.
12 divided by 6 is 2
2 = p
OR
p = 2
Answer:
1. The change per week is $40 as it is the coefficient.
2. The starting amount is $550 as it is the constant.
Answer:
V(x,y,z) ≈ 61.2 in
Step-by-step explanation:
for the function f
f(X)=x³
then the volume will be
V(x,y,z)= f(X+h) - f(X) , where h= 0.2 (thickness)
doing a Taylor series approximation to f(x+h) from f(x)
f(X+h) - f(X) = ∑fⁿ(X)*(X-h)ⁿ/n!
that can be approximated through the first term and second
f(X+h) - f(X) ≈ f'(x)*(-h)+f''(x)*(-h)²/2 = 3*x²*(-h)+6*x*(-h)²/2
since x=L=10 in (cube)
f(X+h) - f(X) ≈ 3*x²*(-h)+6*x*(-h)²/2 = 3*L²*h+6*L*h²/2 = 3*L*h*(h+L)
then
f(X+h) - f(X) ≈ 3*L*h*(h+L) = 3* 10 in * 0.2 in * ( 0.2 in + 10 in ) = 61.2 in
then
V(x,y,z) ≈ 61.2 in
V real = (10.2 in)³-(10 in)³ = 61 in
Answer:
(4cos150, 4sin150) or (4cos5pi/6, 4sin5pi/6)
Step-by-step explanation:
Given the rectangular coordinate
(2√3,-2)
x = 2√3
y = 2
For polar coordinate;
x =r cos theta
y = rsin theta
r = √x²+y²
r = √(2√3)²+(-2)²
r = √4(3) + 4
r = √12+4
r = 4
theta = arctan(y/x)
theta = arctan(-2/2√3)
theta = arctan(-1/√3)
theta = -30
theta = 180 - 30
theta = 150degrees
x = 4cos 150
y = 4sin150
The polar coordinate is (4cos150, 4sin150) or (4cos5pi/6, 4sin5pi/6)
The polar coordinates of the point are
