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Alex Ar [27]
3 years ago
8

8512x61 what is the break down to get the answer

Mathematics
1 answer:
Nata [24]3 years ago
4 0
To break apart 3 digit numbers, you separate the hundreds digit, the tens digit, and the ones digit. For example, if you were trying to break apart 729, you will separate the hundreds digit, which is 7, the tens digit, which is 2, and the ones digit, which is 9. So, 729 = 700 + 20 + 9. You could do 8500x60+9232 which equals 519,232 and 8512x61= 519,232.
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Troyanec [42]
Reflection across the diagonal y=x. 180 degree clockwise rotation about the origin.
8 0
3 years ago
You were planning on using circles to compare the population of California 37,691,000 Texas 25,675,000 and New York 19,465,000 i
Natali5045456 [20]
The total area of a circle (πR²) Is to be proportional to the population's State.
If proportionality to be maintained then Populations should be in
the ratio R²₁ / R²₂

The population of NY is represented by an area of πR² = π.25 (R=5 Given)
CA/NY =37,691,000 / 19,465,000 = R²₁ / R²₂ = 1.936
==> √(R²₁/R²₂)=√1.936 = R₁/R₂ =1.4 ==> R₁/5 = 1.4 & R(ca) = 7
Same logic for Texas: 25,675,000/19,465,000 = R²(tx)/25 =1.319
==> R(tx) =6.6



3 0
3 years ago
A number cube is rolled 24 times and lands on 2 four times and on 6 three times.
kozerog [31]

Answer:

1/6 times the number cube wil land on 2

Step-by-step explanation:

3 0
3 years ago
Which expression is equivalent to square root 55x^7y6/11x^11y^8
Novay_Z [31]

Answer:

\large\boxed{\sqrt{\dfrac{55x^7y^6}{11x^{11}y^8}}=\dfrac{\sqrt5}{x^2y}}

Step-by-step explanation:

\sqrt{\dfrac{55x^7y^6}{11x^{11}y^8}}=\sqrt{\dfrac{55}{11}\cdot\dfrac{x^7}{x^{11}}\cdot\dfrac{y^6}{y^8}}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\=\sqrt{5x^{7-11}y^{6-8}}=\sqrt{5x^{-4}y^{-2}}\qquad\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\=\sqrt5\cdot\sqrt{x^{-4}}\cdot\sqrt{y^{-2}}=\sqrt5\cdot\sqrt{x^{(-2)(2)}}\cdot\sqrt{y^{(-1)(2)}}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=\sqrt5\cdot\sqrt{(x^{-2})^2}\cdot\sqrt{(y^{-1})^2}\qquad\text{use}\ \sqrt{a^2}=a

=\sqrt5\cdot x^{-2}\cdot y^{-1}\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}\to a^{-1}=\dfrac{1}{a}\\\\=\sqrt5\cdot\dfrac{1}{x^2}\cdot\dfrac{1}{y}=\dfrac{\sqrt5}{x^2y}

6 0
3 years ago
(07.02 LC)<br> What is the greatest common factor of x^8 and x^5?
nydimaria [60]

Answer:x

Step-by-step explanation:

8 0
3 years ago
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