A bag of vegetables contains 6 cups, and each serving is 1/2 a cup. How many servings are in a bag
2 answers:
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The correct value of "x" will be "93".
According to the question,
- A linear pair of sum to 180°,
then
→
→
By adding "6" both sides of the equation, we get
→
→
→
→
Thus "option d" is the right answer.
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So if you want to fit the y-intercepts or "b", on the y-axis you should go by 25's [0, 25, 50, 75, 100...]
If the x-axis <u>does not have to</u> follow the same pattern (25's), you should go by 5's [0, 5, 10, 15, 20...]
y = 7x + 50
y = 2x + 175
First I would plot the y-intercepts for each equation, then plot a few points with x = 5, 10, 15 Then draw a straight line.
The point where the two lines meet/cross paths is your solution. It should be (25, 225) The x-axis is the number of miles, and the y-axis is the total cost. So Truck driver A and B would arrive/be at the same place/meet in 25 miles at the same cost of $225
Answer:
0.013 = 1.3% probability that fifteen employees must be tested in order to find three positives.
Step-by-step explanation:
For each employee, there are only two possible outcomes. Either they test positive, or they do not. The probability of an employee testing positive is independent of any other employee, which means that the binomial probability distribution is used to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
40% of the employees have positive indications of asbestos in their lungs
This means that
Find the probability that fifteen employees must be tested in order to find three positives.
2 during the first 14(given by P(X = 2) when n = 14).
The 15th is positive, with 0.4 probability. So
0.0317*0.4 = 0.013.
0.013 = 1.3% probability that fifteen employees must be tested in order to find three positives.