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Scilla [17]
3 years ago
12

Investors buy a studio apartment for $140,000. Of this amount, they have a down payment of

Mathematics
2 answers:
Alex73 [517]3 years ago
7 0

Answer:

Step-by-step explanation:

if the price of the apartment is 140,000 dollars

lets find out how much is 1%

140,000/100=1400

42,000/1400=30  

42,000 is 30% of the apt price

49,000/1400=35

49,000 is 35% of the apt price

vovangra [49]3 years ago
4 0

Answer:

their down payment is 30%

Step-by-step explanation:

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Deirdre is factoring the polynomial x2 + 2x – 24. Which combination can she use to replace the middle term, 2x?
mafiozo [28]

to replace 2x we need +6x-4x

3 0
3 years ago
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Meg is 6 years older than Victor. Meg's age is 2 years less than five times Victor's age. The equations below model the relation
Verdich [7]

Since no possible correct method is posted, I will suggest a couple.

Method 1: guess and check

Works well for simple problems involving integers like this one.

Victor's age must be zero or greater than one, say one.

Guess v=1, find m=v+6=7, check m=5v-2=5-2=3 no good.

we need to make v bigger

Guess v=2, find m=v+6=2+6=8, check m=5v-2=5*2-2=8 ✔

So v=2, m=8.

Method 2:

Solve the system of two equations.

since the left-hand sides is m in both equations, and since m=m, we just have to equate the right-hand sides to solve for v.

5v-2=v+6

Solve for v

5v-v = 6+2

4v=8

v=2,

so again, v=2, m=v+6=2+6=8.

6 0
3 years ago
Which expression equals 6 when a = 5 and b = 1/3? Circle all that apply.
Troyanec [42]

Answer:

A

Step-by-step explanation:

5 0
3 years ago
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Simplify
Diano4ka-milaya [45]

Answer:

\huge\boxed{\sqrt[4]{16a^{-12}}=2a^{-3}=\dfrac{2}{a^3}}

Step-by-step explanation:

16=2^4\\\\a^{-12}=a^{(-3)(4)}=\left(a^{-3}\right)^4\qquad\text{used}\ (a^n)^m=a^{nm}\\\\\sqrt[4]{16a^{-12}}=\bigg(16a^{-12}\bigg)^\frac{1}{4}\qquad\text{used}\ a^\frac{1}{n}=\sqrt[n]{a}\\\\=\bigg(2^4(a^{-3})^4\bigg)^\frac{1}{4}\qquad\text{use}\ (ab)^n=a^nb^n\\\\=\bigg(2^4\bigg)^\frac{1}{4}\bigg[(a^{-3})^4\bigg]^\frac{1}{4}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=2^{(4)(\frac{1}{4})}(a^{-3})^{(4)(\frac{1}{4})}=2^1(a^{-3})^1=2a^{-3}\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}

=2\left(\dfrac{1}{a^3}\right)=\dfrac{2}{a^3}

5 0
3 years ago
Divide using synthetic division: (2x^4+2x^3+-12x^2+x+6)/(x+3)​
kap26 [50]

Synthetic division yields

..... ||   2    2   -12    1      6  

-3  ||        -6    12    0    -3

= = = = = = = = = = = = = =

..... ||   2   -4     0    1      3

which translates to

\dfrac{2x^4+2x^3-12x^2+x+6}{x+3}=2x^3-4x^2+1+\dfrac3{x+3}

5 0
3 years ago
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