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3 years ago

Explain how to solve the equation that is given AND solve. -3x + 4 = 25

Mathematics

2 answers:

sesenic [268]3 years ago

3 0

Answer:
x = -7

Explanation:
25 - 4 = 21
21 / -3 = -7

Sophie [7]3 years ago

3 0

The answer is -7 steps are shown down below

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The bank balance was $1,234,567 on January 31. In February, we received $825k on paid invoices, and had $198k in cost of sales,

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Answer:

April Beginning Balance $ 1,633,427

Step-by-step explanation:

The closing balance of January is the opening balance of February

February,

Opening Balance $1,234,567

Add Payment received on invoices $825k

Less Cost of sales $198k,

Less Overheads $356k ,

Less Other Expenses $92k .

February Ending Balance $ 1,413, 567

March

Beginning Balance $ 1,413, 567

Add Payment received on invoices $825k *1.12= 924 k

Less Cost of sales $198k *1.09= 215.82k

Less Overheads $356k *1.09= 388.04k

Less Other Expenses $92k *1.09= 100.28k

March Ending Balance = $ 1,633,427

April Beginning Balance $ 1,633,427

Treating the Costs of Sales, Overheads and the other expenses as the expenses paid out of the Bank Balance meaning no accounts payable or other cash paid.

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3 years ago

I need help with this question. It is due today and if I email my teacher, she doesn’t respond till 10 pm. So please anyone who

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Answer:

Step-by-step explanation: rip this kid aye

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3 years ago

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In a random sample of 80 teenagers, the average number of texts handled in one day is 50. The 96% confidence interval for the me

Naily [24]

Answer:

Standard deviation of the sample = 17.421

Step-by-step explanation:

We are given that in a random sample of 80 teenagers, the average number of texts handled in one day is 50.

Also, the 96% confidence interval for the mean number of texts handled by teens daily is given as 46 to 54.

So, sample mean, $xbar$ = 50 and Sample size, n = 80

Let sample standard deviation be s.

96% confidence interval for the mean number of texts, $\mu$ is given by ;

96% confidence interval for $\mu$ = $xbar \pm 2.0537*\frac{s}{\sqrt{n} }$

[46 , 54] = $50 \pm 2.0537*\frac{s}{\sqrt{80} }$

Since lower bound of confidence interval = 46

So, 46 = $50 - 2.0537*\frac{s}{\sqrt{80} }$

50 - 46 = $2.0537*\frac{s}{\sqrt{80} }$

s = $\frac{4*\sqrt{80} }{2.0537}$ = 17.421

Therefore, standard deviation of the sample is 17.421 .

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Answer:

14.50 * 1.32 = $19.14

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