E and F are two events and that P(E)=0.3 and P(F|E)=0.5. Thus, P(E and F)=0.15
Bayes' theorem is transforming preceding probabilities into succeeding probabilities. It is based on the principle of conditional probability. Conditional probability is the possibility that an event will occur because it is dependent on another event.
P(F|E)=P(E and F)÷P(E)
It is given that P(E)=0.3,P(F|E)=0.5
Using Bayes' formula,
P(F|E)=P(E and F)÷P(E)
Rearranging the formula,
⇒P(E and F)=P(F|E)×P(E)
Substituting the given values in the formula, we get
⇒P(E and F)=0.5×0.3
⇒P(E and F)=0.15
∴The correct answer is 0.15.
If, E and F are two events and that P(E)=0.3 and P(F|E)=0.5. Thus, P(E and F)=0.15.
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Answer:
Step-by-step explanation:
By MVT,
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Moreover, 
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Hence the largest possible value of f(5) is 13
Answer:
X = 4
Step-by-step explanation:
x2 + 1 = 9
We have to cross 1 over to the other side so that x becomes a value on its own. Because we are it over, the addition sign changes to subtraction which makes the expression,
x2 = 9- 1
x2 = 8
For x to stand alone we have to divide both sides by 2
x 2/2 = x
and 8/2 = 4
Therefore x=4 (Answer)
Answer:
Its D Hope it helps
Step-by-step explanation: