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sergiy2304 [10]
3 years ago
14

Find two integers whose sum is 3 and product is -108.

Mathematics
1 answer:
AleksandrR [38]3 years ago
7 0

Answer:

12 and -9

Step-by-step explanation:

12 x -9 = -108

12 + -9 = 3

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3 years ago
A playground is rectangular with a length of 24 miles. If the area of the playground is 812 square miles, what is its width? Ans
soldi70 [24.7K]

Answer:

33(5/6) sq miles

Step-by-step explanation:

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8 is non repeating

3 is repeating

For nominator subtract the non repeating    (83-8 = 75)

For  denominator :  one 9 for each non repeating,one zero for each repeating (only 3 is repeating,then one zero)

  75/90  = 5/6

3 0
3 years ago
There were 10 bunches of roses and tulips. Each bunch had 5 of the same flowers. There were 2 more bunches of tulips than roses.
____ [38]

Answer:

7

Step-by-step explanation:

6 0
3 years ago
Can you help me with my work
andrezito [222]

Answer:

1. x = ±9

2. x=\pm \sqrt{13}

3. 12 and -12.

4. Antoine is incorrect. There exists two solutions x=5 and x= -5.

Step-by-step explanation:

According to the questions,

Problem 1. x^{2}-81=0 i.e. x^{2}=81 i.e. x = ±9.

Problem 2. 2x^{2}-26=0 i.e. x^{2}-13=0 i.e. x^{2}=13 i.e. x=\pm \sqrt{13}

Problem 3. [tex]f(x)=x^{2}-144[tex]

To find the roots, we take, [tex]x^{2}-144=0[tex] i.e. [tex]x^{2}=144[tex] i.e. x = ±12.

Thus, the options are 12 and -12.

Problem 4. We have [tex]f(x)=x^{2}+25[tex]

For the roots, we take, [tex]x^{2}+25=0[tex] i.e. [tex]x^{2}=25[tex] i.e. x = ±5.

Thus, Antoine is not correct and two solutions namely x=5 and x= -5 exists.

8 0
2 years ago
3x-2=2(x-5)<br><br>find the value of x ​
kipiarov [429]

Now we have to,

find the required value of x.

Let's begin,

→ 3x-2 = 2(x-5)

→ 3x-2 = 2x-10

→ 3x-2x = -10+2

→ x = -8

Hence, value of x is -8.

5 0
3 years ago
Read 2 more answers
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