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pogonyaev
2 years ago
7

Graph ∆KLM with vertices K(2,2), L(0,- 1), and M(-3,2). Graph ∆K'L'M' with a scale factor of 2. What are the coordinates of the

new vertices?
Mathematics
1 answer:
olasank [31]2 years ago
5 0

Answer:

The coordinates of the new vertices are:

K'(4,4), L'(0,- 2), and M'(-6,4).

Step-by-step explanation:

In order to dilate a shape by 2, you can simply multiply the coordinates of the orignal triangle each by 2 to find the new coordinates of the new vertices.

K(2,2), L(0,- 1), and M(-3,2)

K'(2*2,2*2), L'(0*2,- 1*2), and M'(-3*2,2*2).

Now become...

K'(4,4), L'(0,- 2), and M'(-6,4).

You can now graph ∆K'L'M' using these coordinates.

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Answer:

D. y = -5^x – 27

Step-by-step explanation:

Find the negative reciprocal of the slope of the original line and use the point-slope formula  y − y 1 = m ( x − x 1 )  to find the line perpendicular to  − x + 5 y = 14 .

y = − 5 x − 27                         PERPENDICULAAR

...................................................................................................................................................

Find the slope of the original line and use the point-slope formula  y − y 1 = m ( x − x 1 )  to find the line parallel to  − x + 5 y = 14 .

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What are the missing angle measures in triangle ABC?
Finger [1]

we know that

In the right triangle ABC

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so

Step 1

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we know that

tan\  B=\frac{opposite\  side\  angle\  B}{adjacent\  side\  angle\  B}

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Step 2

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