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3 years ago

I need help guys please help

Mathematics

1 answer:

VikaD [51]3 years ago

8 0

Slope=rise/run

rise: 7
run: 6

so it would be -7/6

(mark brainliest if right pls)

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Ramiro randomly surveyed 60 students during one of his school's basketball games and asked if they preferred cheese, pepperoni,

Over [174]

Answer:

590. 2 students

Step-by-step explanation:

39/60= 65%

65% of 908=590. 2

4 0

3 years ago

Read 2 more answers

Smith Engineering is in the process of reviewing the salaries of their surveyors. During this review, the company found that an

siniylev [52]

Answer:

T = 3.5 hours

Step-by-step explanation:

this is a rate problem.

an experienced surveyor takes 7 hours to survey a roadbed

an apprentice surveyor takes 9 hours to survey a roadbed

the rate of the experienced surveyor = $\frac{1}{7}$

the rate of the apprentice surveyor = $\frac{1}{9}$

if the two work together , $\frac{1}{T} =\frac{1}{7} +\frac{1}{9}$

T = $\frac{56}{16}$

T = 3.5 hours

3 0

3 years ago

Which set represents the domain of function shown? {(-3,6),(0,2),(4,7),(11,15)}

ValentinkaMS [17]

Answer:

{-3,0,4,11}

Step-by-step explanation:

{(-3,6),(0,2),(4,7),(11,15)}

The domain is the input values, or x coordinates

{-3,0,4,11}

8 0

4 years ago

Find each product or quotient.

solniwko [45]

-38(-3) = 114

-72/(-12) = 6

-9 x 23 = -207

-150/5 = -30

564 / -4 = -141

<h3>Solution:</h3>

Given that, we have to find each product or quotient

-38(-3)

It is a product, so we have to find product value

$-38(-3)=38 \times 3=114$

-72 / (-12)

It is division, so we have to find the quotient

$\frac{-72}{-12}=\frac{72}{12}=6$

-9 x 23

It is a product, so we have to find product value

$-9 \times 23=-207$

- 150 / 5

It is division, so we have to find quotient

$\frac{-150}{5}=-30$

564 / -4

It is division, so we have to find the quotient

$\frac{564}{-4}=-141$

3 0

4 years ago

I am confused on numbers 25 and 29, the instructions are at the top.

kvasek [131]

#25 is fairly simple. Plug in -4 and 3 into the equation, and the extraneous root will be the one that does not work.
$\sqrt{12-(-4)} = \sqrt{16} = \frac{+}{}4$
Extraneous root in this case is positive four since +4≠-4
 $\sqrt{12-3} = \sqrt{9} = \frac{+}{}3$
In this case it's negative 3, since -3≠3

#29 can be turned into a quadratic equation.
$x= \sqrt{2x+3}$
Square both sides to get
$x^{2}=2x+3$
Then bring the 2x+3 to the other side, setting the quadratic equal to zero.
$x^{2}-2x-3=0$
Factor to find that it's equivalent to
(x-3)(x+1)=0
Therefore x is equal to positive 3 and negative 1. Plug both back into the original equation. Whichever does not work is the extraneous root, and the answer is the one that does.
 $x= \sqrt{2x+3}$
 $3= \sqrt{2(3)+3}$
 $3= \sqrt{9}$
Extraneous root would be negative 3.

 $-1= \sqrt{2(-1)+3}$
 $-1= \sqrt{1}$
Extraneous root would be positive 1.

Your answers are positive 3 and negative 1.
Extraneous roots are negative 3 and positive 1.

3 0

3 years ago