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IRISSAK [1]
2 years ago
15

I need help plz percent equations the question is blank% of 16 = 12

Mathematics
1 answer:
ch4aika [34]2 years ago
5 0

Answer:

16 x 0,75

(0,75 = 3/4) so you could take 3 x 16 = 48 and then take 48/4 and the answer should be 12 but the percent is 75%

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An element a basic substance that can’t be
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Answer:

Simplified

Step-by-step explanation:

Examples can be hydrogen, oxygen, gold

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If it takes 930 kg of food to feed a pair of elephants for 3 days how much food would u need to feed them for a week?
bagirrra123 [75]

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The mean life of a television set is 119 months with a standard deviation of 14 months. If a sample of 74 televisions is randoml
irina [24]

Answer:

50.34% probability that the sample mean would differ from the true mean by less than 1.1 months

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 119, \sigma = 14, n = 74, s = \frac{14}{\sqrt{74}} = 1.63

If a sample of 74 televisions is randomly selected, what is the probability that the sample mean would differ from the true mean by less than 1.1 months

This is the pvalue of Z when X = 119 + 1.1 = 120.1 subtracted by the pvalue of Z when X = 119 - 1.1 = 117.9. So

X = 120.1

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{120.1 - 119}{1.63}

Z = 0.68

Z = 0.68 has a pvalue of 0.7517

X = 117.9

Z = \frac{X - \mu}{s}

Z = \frac{117.9 - 119}{1.63}

Z = -0.68

Z = -0.68 has a pvalue of 0.2483

0.7517 - 0.2483 = 0.5034

50.34% probability that the sample mean would differ from the true mean by less than 1.1 months

8 0
3 years ago
Btw the answer has to be in fraction form if it’s a decimal then we will need to convert it into a fraction please help me
Misha Larkins [42]

Answer:

217 = 217/100 = 2.17

Step-by-step explanation:

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3w Plus 8g plus 7w plus 6W
Pachacha [2.7K]

Answer:

24wg

Step-by-step explanation:

3w+8g+7w+6w = 24wg

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