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ahrayia [7]
3 years ago
7

Can someone pleaseeee help me

Mathematics
1 answer:
Natalka [10]3 years ago
5 0

Answer:

a). Common difference = 4

b). T_n=4n+3

c). 51st term = 207

Step-by-step explanation:

Given arithmetic sequence is,

7, 11, 15, 19......

a). Common difference = Second term - First term

                                      = 11 - 7

                                      = 4

b). nth term of an arithmetic sequence is given by,

   T_n=a+(n-1)d

   Here, n = number of term

   a = First term

   d = common difference

   By substituting the values in the given formula,

   T_n=7+(n-1)4

   T_n=4n+3

c). 51st term of the sequence will be,

   T_{51}=7+(51-1)4

         = 7 + 200

         = 207

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