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3 years ago

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Let the base of a solid be the first quadrant region bounded by y=1-((x^2)/4), the x- axis and the y-axis. Suppose that cross se

ctions perpendicular to the x-axis are squares. Find the volume of the solid.

1 answer:

barxatty [35]3 years ago

4 0

Answer:

bjttkkhdvehakasgsgsbdhdndns thats the answer pick me brainliest

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I need help, sleps plzz , i dont understand plzzz dont ignoree!!!!!!!!!!!!

denpristay [2]

Answer:

x = $\frac{3+\sqrt{105} }{8} , \frac{3-\sqrt{105} }{8} x=1.655,-0.905$

Step-by-step explanation:

3x+6 = 4x^2

4x^2 -3x -6 = 0

x = $\frac{3+\sqrt{105} }{8} , \frac{3-\sqrt{105} }{8} x=1.655,-0.905$

7 0

3 years ago

If fixed cost of 20 article is 500 and variable cost for each article is 40. Find the total cost function? Also ,find the total

Deffense [45]

Answer:

Cost function = 40a + 500

Cost of 90 articles = $4,100

Step-by-step explanation:

The fixed cost is $500 and it will.not change regardless of production level.

The Variable cost is $40 and increases by every additional unit produced.

Assume the number of articles produced is a.

Cost function would be:

Total cost = Variable cost * Number of articles + Fixed cost

TC = 40a + 500

Using this, the cost of 90 articles is:

= 40 * 90 + 500

= $4,100

6 0

3 years ago

Please help me out with this question

I am Lyosha [343]

Answer:

no. 4

Step-by-step explanation:

6 0

4 years ago

Ghella [55]

X=10 is the answer to this

4 0

3 years ago

Read 2 more answers

Dy/dx = y/x , y(1) = −2

s2008m [1.1K]

Start with

$\dfrac{dy}{dx}=\dfrac{y}{x}$

Separate the variables:

$\dfrac{dy}{y} = \dfrac{dx}{x}$

Integrate both parts:

$\displaystyle \int \dfrac{dy}{y} = \int\dfrac{dx}{x}$

Which implies

$\log(y) = \log(x)+c$

Solving for y:

$y = e^{\log(x)+c} = e^{\log(x)}e^c=xe^c$

Since $e^c$ is itself a constant, let's rename it $c_1$ .

Fix the additive constant imposing the condition:

$y(1) = c_1\cdot 1 = -2\iff c_1=-2$

So, the solution is

$y(x) = -2x$

5 0

3 years ago