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Sphinxa [80]
3 years ago
15

Let the base of a solid be the first quadrant region bounded by y=1-((x^2)/4), the x- axis and the y-axis. Suppose that cross se

ctions perpendicular to the x-axis are squares. Find the volume of the solid.
Mathematics
1 answer:
barxatty [35]3 years ago
4 0

Answer:

bjttkkhdvehakasgsgsbdhdndns thats the answer pick me brainliest

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13 ft<br> 5<br> ft<br> 5 ft<br> Volume:
steposvetlana [31]

Hi!

So all we would need to do is 13*5*5=325. The volume is 325ft cubed.

Hope this helps!

7 0
3 years ago
Pls help me solve it!
vekshin1

Answer:

A= 40°

B= 35°

C= 15°

Step-by-step explanation:

Since it says if the triangles were accurately drawn, then A would be the same  degree as Q. C would be the same degree as P. B would be the same degree as R. Since R's degree is missing I knew that a obtuse triangle was 90°. I added 40+15 and got 55. Then i subtracted 90-55 and got 35. So the unknown value would be 35°.

I hope this helps.

3 0
3 years ago
What is the answer for number 7?
aivan3 [116]

Answer:

Step-by-step explanation:

x=30

m=abe=180

8 0
3 years ago
**hint** Find the hypotenuse and then subtract that from the distance he actually traveled.
icang [17]

Answer:

10 miles

Step-by-step explanation:

5 0
3 years ago
Which equation has a graph that is a parabola with a vertex at (5,3)?
lara [203]

Answer:

y =  (x -5)² + 3.

Step-by-step explanation:

Given : parabola with a vertex at (5,3).

To find : Which equation has a graph that is a parabola.

Solution : We have given vertex at (5,3).

Vertex form of parabola : y = (x -h)² + k .

Where, (h ,k )  vertex .

Plug h = 5  , k= 3 in vertex form of parabola.

Equation  :y =  (x -5)² + 3.

Therefore, y =  (x -5)² + 3.

6 0
3 years ago
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