Find a so that the point (-1, 2) is on the graph of f(x)=ax^2+5.
1 answer:
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The graph is attached.
Answer:
(-2.2, 4) and (8.2, 4)
Step-by-step explanation:
In an ellipse, there is a minor radius and a major radius.
Let major radius be = a
Let minor radius be= b
From the graph, we are given:
Major radius, a = 6
Minor radius, b = 3
Now, let's find the distance from the center to the focus using the formula:
Substituting values, we have:
≈ 5.2
We can see from the graph that center coordinate is (3, 4). Therefore, the approximate locations of the foci of the ellipse would be:
(3-5.2, 4) and (3+5.2, 4)
= (-2.2, 4) and (8.2, 4)
