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tatuchka [14]
3 years ago
7

Find a so that the point (-1, 2) is on the graph of f(x)=ax^2+5.

Mathematics
1 answer:
Gnesinka [82]3 years ago
4 0
We are asked to determine the value of a such that the function f(x) = ax^2 + 5 is fit for the point given (-1,2). In this case, we substitute 2 to y and -1 to x. The result is then 2 = a*(-1)^2 + 5 ; 2 = a + 5; a is then equal to -3
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3 years ago
A rectangle has a length that is three feet more than twice it's width. The perimeter of the rectangle is 78 feet. State the val
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\rm \implies 2(Length + Width) = 78 \\  \\  \rm \implies 2(2w + 3 + w) = 78 \\  \\  \rm \implies 2(3w + 3) = 78 \\  \\  \rm \implies 2 \times 3(w + 1) = 78 \\  \\  \rm \implies 6(w + 1) = 78 \\  \\  \rm \implies w + 1 =  \dfrac{78}{6}  \\  \\  \rm \implies w + 1 = 13 \\  \\  \rm \implies w = 13 - 1 \\  \\  \rm \implies w = 12 \: ft

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Step-by-step explanation:

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3 years ago
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Please give brainliest if you can!

Hope this helps!! :)
8 0
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