Answer:
1
Step-by-step explanation:

Answer:
the length is 22 and the width is 18
Step-by-step explanation:
The perimeter is 2(l) + w(2)
w is the width and l is the length
if you plug in 22 and 18 you get
2(22)+(2)18
then you do multiplication to get
44+36
then you add and you get 80
Answer:
26.5%
Step-by-step explanation:
<u>Increasing Percentages</u>
When sequential percentages increasing are computed, each increase applies to the previous result, instead of the first quantity. That is why sometimes the final results may be confusing. For example, increasing 10% and then 15% will not be the same as increasing a total of 25%.
The average test scores of RSM students first increased by 10%. It means that some quantity C increased by

Now the average test scores are

A new increasing occurred by 15%, and the previous quantity must be multiplied by 1.15, so the final average test scores are

It means that the total increasing was

The value of x is 5. Thus, the correct statement is:
x = 5 is a true solution because log subscript 2 Baseline (16) = 4
<h3>Data obtained from the question </h3>
- Log₂ (x + 11) = 4
- Value of x =?
<h3>How to determine the value of x </h3>
Log₂ (x + 11) = 4
x + 11 = 2⁴
x + 11 = 16
Collect like terms
x = 16 – 11
x = 5
<h3>**Check** </h3>
Log₂ (x + 11) = 4
x = 5
Log₂ (5 + 11) = 4
Log₂ 16 = 4
Find the value of Log₂ 16
Log₂ 16 = n
16 = 2ⁿ
2⁴ = 2ⁿ
n = 4
Thus,
Log₂ 16 = 4
Therefore, the correct answer to the question is:
x = 5 is a true solution because log subscript 2 Baseline (16) = 4
Complete question
Which of the following is true regarding the solution to the logarithmic equation below? log Subscript 2 Baseline (x + 11) = 4. x + 11 = 2 Superscript 4. x + 11 = 16. x = 5. x = 5 is not a true solution because log Subscript 5 Baseline (16) not-equals 2 x = 5 is not a true solution because log Subscript 5 Baseline (16) not-equals 4 x = 5 is a true solution because log Subscript 2 Baseline (16) = 4 x = 5 is a true solution because log Subscript 4 Baseline (16) = 2
Learn more about Logarithm equation:
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