Assume ladder length is 14 ft and that the top end of the ladder is 5 feet above the ground.
Find the distance the bottom of the ladder is from the base of the wall.
Picture a right triangle with hypotenuse 14 feet and that the side opposite the angle is h. Then sin theta = h / 14, or theta = arcsin 5/14. theta is
0.365 radian. Then the dist. of the bot. of the lad. from the base of the wall is
14cos theta = 14cos 0.365 rad = 13.08 feet. This does not seem reasonable; the ladder would fall if it were already that close to the ground.
Ensure that y ou have copied this problem accurately from the original.
The solution to the equation includes both the positive and negative portions of the solution. x = 12, -12
Answer:
On average, the land moved 0,14 cm each year.
Step-by-step explanation:
To know how much did, on average, the land move, we should divide the total number of cm over the total number of years:
x=24.8 cm/175 years
x=0,1417 cm each year
If we divide years over cm we will get x in years each cm, which is wrong.
Because the problem asks for the answer rounded to the hundredths place:
x= 0,14 cm each year
Answer:4.1
Step-by-step explanation:
c=AB
C=26°
B=122°
b=8
Using sine rule
c/sinC = b/sinB
c/sin26=8/sin122
Sin26=0.4384
Sin122=0.8480
c/0.4384=8/0.8480
Cross multiply
c x 0.8480=8 x 0.4384
c x 0.8480=3.5072
Divide both sides by 0.8480
(c x 0.8480)/0.8480=3.5072/0.8480
c=4.1
Answer:
12) 5.96 ; 13)
Step-by-step explanation:
12). x and 5 are legs, so
opposite leg/adjacent leg = tangent 40°
5/x= tan40°, 5= x*tan40°, x= 5/tan40° ≈ 5.96
13). 15 is opposite leg
24 is hypotenuse
opposite leg/hypotenuse = sin(x)
sin(x) = 15/24
x = arcsin(15/24) ≈ 38.68°
