Answer: c. 1498
Step-by-step explanation:
Given : Preliminary estimates suggest that about 58% of students at a state university favor implementing an honor code.
i.e. p = 0.58
Significance level :
Critical value :
Margin of error =
The formula to find the sample size is given by :-
Hence, the minimum sample size needed = 1498
The answer is C because your times each number by 2 6 times 2 is 12, 12 times 2 is 24, 24 times 2 is 48 and you do it 8 times until you get your answer which is 768 bulbs
<h3>
Answer: 90 cubic meters</h3>
Each triangle has a base of 10 and height of 3.6
area of triangle = 0.5*base*height = 0.5*10*3.6 = 18 square meters
multiply this with the height of the prism (5 meters) to get 18*5 = 90 cubic meters. I'm using the idea that,
volume of prism = (area of base face)*(height of prism)
The notation "m^3" is shorthand for "cubic meters"
We do not use the other dimensions of 9 m and 7 m.
The number of students would not change between before the test and after the test. 3+8 and 4+7 both = 11 so finding out how many students would equal one ratio can then be used to find how many equal 3 and 8.
If 92 students are equal to 4 in the ratio, then 1 in the ratio is worth 23 students. This is important as then when you times 23 by 7 you find out how many students there are in the regular maths class, 161 students. Plussing these two together gives you a total of 253 students.
Using this 253 you can divide it by 11 to find out how much 1 number would be in the ratio, it equals 23. Using this you can then times 23 by both 3 and 8 to find the original class sizes, 3x23 = 69, and 23x8 = 184.
Making the origional class size of the advaced class 69 studnets, and the regular maths class size 184.
Answer: 3/7
Step-by-step explanation: