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RUDIKE [14]
3 years ago
8

HELP HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
NNADVOKAT [17]3 years ago
6 0

Answer:

6.75

Step-by-step explanation:

A of rectangle = 2*1.5=3

A or triangle= (7-2)*1.5/2 = 5*1.5/2 =3.75

Area trapezoid =A rectangle +Atriangle = 3+3.75=6.75

mihalych1998 [28]3 years ago
4 0

Answer:

C : 6.75 yd.

Step-by-step explanation:

first, you divide the trapezoid into two shapes, a square, and a triangle. For the square's area, you multiply 2yd and 1,5 yd to get 3 yd. Then for the triangle's area, since the bottom side of the trapezoid is a side for both the triangle and the square, the square already took 2yd if that makes sense. You multiply 5yd and 1.5 yd to get 7.5 yd. Since its a triangle, you divide the area of the triangle by 2, which is 3.75 yd. To get the total area of the trapezoid, you then add 3yd plus 3.75 yd to get 6.75 yd. ²

hope this helps

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A well-designed experiment should have which of the following characteristics?
igor_vitrenko [27]

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Step-by-step explanation:

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3 years ago
Y'all i need help immediately
adoni [48]

Answer:

Option B

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3 0
3 years ago
I’m not understanding the answer listed on this site to the following question:
kobusy [5.1K]
Okay, I think I understand this. Our first step is to solve how long the string is after he used some of it to tie the package. I have a feeling we have to subtract 7/8 - 1/5. Find a least common multiple (in this case, it's 40) and our new fractions are 35/40 and 8/45. Subtract:

35/40 - 8/40 = 27/40.

I don't think this can be simplified down any further as they do not have any common factors. So with that in mind, let's divide 27/40 with 5/1 (5/1 is basically 5 wholes but in fraction version)

When dividing fractions, you want to use the KCF technique (my old math teacher taught me this). Keep the first fraction the same (in this case, 27/40), change the sign from multiplication to division, and flip 5/1 to get it's reciprocal, 1/5. The equation will look like this:

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If this is wrong, please let me know, but this is what I got out of this question. I hope this helped you :)
4 0
3 years ago
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