Red/green color blindness is passed down from mother to son and so we can conclude that the last two statements are wrong. Which are that "She cannot be homozygous recessive for the gene for color blindness" and "she cannot be a heterozygous carrier of the gene for color blindness "From the information proved we know that the mother must have at least one allele for color blindness.
My guess would be areas that have very little flat lands. probably your forest. sorry if this doesnt help
Answer:
The parent's genotypes are:
Ddpp - tall, white parent
ddPp - dwarf, purple parent.
Explanation:
This question involves two different genes coding for height and flower color in pea plants. The alleles for tallness (D) and purple color (P) are dominant over the alleles for dwarfness (d) and white color (p) respectively.
According to this question, a tall plant with white flowers is crossed with a dwarf plant with purple flowers to produce the following proportion of offsprings: 1/4 tall purple, 1/4 tall white, 1/4 dwarf purple, and 1/4 dwarf white.
Since some of the offsprings contain recessive alleles for both or either genes, the dominant traits of the parent is controlled by an heterozygous genotype. This means that the tall plant with white flowers has a genotype: Ddpp while the dwarf plant with purple flowers has the genotype: ddPp. In a cross between Ddpp × ddPp, 1/4 of each combination of alleles is produced in the offsprings (see punnet square in the attachment).
The second one probably because of the law of conservation of mass where mass is not created or destroyed, so the mass has to be the same.