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sweet-ann [11.9K]
2 years ago
8

Mr. Meadows has a 6 and a 1/2 gallon bucket. His dipping can hold one and a 1/2 gallons. 3 times this year to dip into the pond

with the dipping can to fill the bucket to the top
Mathematics
1 answer:
joja [24]2 years ago
4 0

Answer:4

Step-by-step explanation:

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42,500 X 0.10 = $4250.
You owe $4250!!
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X+y=13 and 1/2x+y=10
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3 years ago
James has $5.00 more than three times what Catherine has. Together they have $41.00. How much does each student have?
Tpy6a [65]
Hey.

acc'g to the conditions :

Let Catherine has x
and James has 5 + 3x

Then,

5 + 4x = 41 \\ \\ \implies 4x +5 -5 = 41-5 \\ \\ \implies 4x = 36 \\ \\ \implies x= \dfrac{36}{4} \\ \\ \implies x = 9

Hence

• Catherine has = x = $9,
• and James has = 5 +3x = 5 + 3(9) = $32

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7 0
2 years ago
How do you Solve d+7/−3=4?
vova2212 [387]

Answer:

One solution was found :

                  d = 19/3 = 6.333

Step-by-step explanation:

Step by step solution :

Step  1  :

            7

Simplify   ——

           -3

Equation at the end of step  1  :

        7    

 (d +  ——) -  4  = 0

       -3    

Step  2  :

Rewriting the whole as an Equivalent Fraction :

2.1   Adding a fraction to a whole

Rewrite the whole as a fraction using  -3  as the denominator :

         d     d • -3

    d =  —  =  ——————

         1       -3  

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

2.2       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

d • 3 + 7 • -1     3d - 7

——————————————  =  ——————

      3              3  

Equation at the end of step  2  :

 (3d - 7)    

 ———————— -  4  = 0

    3        

Step  3  :

Rewriting the whole as an Equivalent Fraction :

3.1   Subtracting a whole from a fraction

Rewrite the whole as a fraction using  3  as the denominator :

        4     4 • 3

   4 =  —  =  —————

        1       3  

Adding fractions that have a common denominator :

3.2       Adding up the two equivalent fractions

(3d-7) - (4 • 3)     3d - 19

————————————————  =  ———————

       3                3  

Equation at the end of step  3  :

 3d - 19

 ———————  = 0

    3  

Step  4  :

When a fraction equals zero :

4.1    When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 3d-19

 ————— • 3 = 0 • 3

   3  

Now, on the left hand side, the  3  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  3d-19  = 0

Solving a Single Variable Equation :

4.2      Solve  :    3d-19 = 0

Add  19  to both sides of the equation :

                     3d = 19

Divide both sides of the equation by 3:

                    d = 19/3 = 6.333

One solution was found :

                  d = 19/3 = 6.333

6 0
3 years ago
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