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2 years ago

What is the perimeter of a rectangle with length 8 and area=72 please show work

Mathematics

1 answer:

lawyer [7]2 years ago

4 0

Answer:

Area = length x width. Solution : Area = 5 x 10. Area = 50 in². Area & Perimeter of a Rectangle calculator uses length and width of a rectangle, and calculates the perimeter, area and diagonal length of the rectangle. It is an online Geometry tool requires two length sides of a rectangle.

Step-by-step explanation:

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Twenty years ago a small town in Texas had a population of 10,000. The population has increased 8% each year

yan [13]

Answer:

Step-by-step explanation:

8% = .08 in decimal form

10 000 ( 1 + .08)^10 =

8 0

1 year ago

Select the correct answer from each drop-down menu. ronald is buying a rectangular chest to store his carpentry tools. the heigh

shepuryov [24]

The function that represents the volume of the chest is 40.

What is a volume simple definition?

The amount of space occupied by a three-dimensional figure as measured in cubic units (as inches, quarts, or centimeters) cubic capacity.
The amount of a substance occupying a particular volume.

When the Area of rectangular chest:

A(x) = 20√x /3

⇒ Volume of chest = Base area x Height

Therefore:

(X + 6) × 20√x /3

(20x√x /3 ) + (20 × 6√x/3)

(20x√x /3 ) + (20 × 2 × 3√x/3)

(20x√x/3) + 40√x

Therefore, the correct answer for the drop-down menu is that the first blank is multiply and the second blank is 40.

Learn more about Volume

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8 0

1 year ago

Calculus Problem

Roman55 [17]

The two parabolas intersect for

$8-x^2 = x^2 \implies 2x^2 = 8 \implies x^2 = 4 \implies x=\pm2$

and so the base of each solid is the set

$B = \left\{(x,y) \,:\, -2\le x\le2 \text{ and } x^2 \le y \le 8-x^2\right\}$

The side length of each cross section that coincides with B is equal to the vertical distance between the two parabolas, $|x^2-(8-x^2)| = 2|x^2-4|$ . But since -2 ≤ x ≤ 2, this reduces to $2(x^2-4)$ .

a. Square cross sections will contribute a volume of

$\left(2(x^2-4)\right)^2 \, \Delta x = 4(x^2-4)^2 \, \Delta x$

where ∆x is the thickness of the section. Then the volume would be

$\displaystyle \int_{-2}^2 4(x^2-4)^2 \, dx = 8 \int_0^2 (x^2-4)^2 \, dx \\\\ = 8 \int_0^2 (x^4-8x^2+16) \, dx \\\\ = 8 \left(\frac{2^5}5 - \frac{8\times2^3}3 + 16\times2\right) = \boxed{\frac{2048}{15}}$

where we take advantage of symmetry in the first line.

b. For a semicircle, the side length we found earlier corresponds to diameter. Each semicircular cross section will contribute a volume of

$\dfrac\pi8 \left(2(x^2-4)\right)^2 \, \Delta x = \dfrac\pi2 (x^2-4)^2 \, \Delta x$

We end up with the same integral as before except for the leading constant:

$\displaystyle \int_{-2}^2 \frac\pi2 (x^2-4)^2 \, dx = \pi \int_0^2 (x^2-4)^2 \, dx$

Using the result of part (a), the volume is

$\displaystyle \frac\pi8 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{256\pi}{15}}}$

c. An equilateral triangle with side length s has area √3/4 s², hence the volume of a given section is

$\dfrac{\sqrt3}4 \left(2(x^2-4)\right)^2 \, \Delta x = \sqrt3 (x^2-4)^2 \, \Delta x$

and using the result of part (a) again, the volume is

$\displaystyle \int_{-2}^2 \sqrt 3(x^2-4)^2 \, dx = \frac{\sqrt3}4 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{512}{5\sqrt3}}$

7 0

2 years ago

Using the figure, the transformation shown is o. Reflection o. Rotation o. Translation

Grace [21]

Answer:

Its a Translation because all they did with it was move it. It never changed size or shape.

Step-by-step explanation:

8 0

3 years ago

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ILL MARK BRAINLEST JUST HELP PLEASEEE

krek1111 [17]

Answer:

I think its 336. I might be wrong though, But I hope I am right.

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers