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Luden [163]
3 years ago
7

For a right triangle if a = 11in , c = 15 in find b Quickkk please help

Mathematics
2 answers:
Furkat [3]3 years ago
4 0
The answer to this problem is 2√26

15^2-11^2 = 104
sq root 104
andre [41]3 years ago
4 0

Answer:

\huge\boxed{ \boxed{  \sf{2 \sqrt{26} }}}

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • Pythagoras theorem
  • PEMDAS
<h3>tips and formulas:</h3>
  • \sf Pythagoras\: theorem:\\ \sf a²+b²=c²
<h3>given:</h3>
  • a=11 in
  • c=15 in
<h3>let's solve:</h3>

\sf step - 1 : make \: b \: the \: subject \: of \: the \: equation

  1. \sf \: shift \:  {a}^{2}  \: to  \: the\: left \: hand \: side \: and \: change \: its \: sign :   \\ \tt  {b}^{2} =  {c}^{2}  -  {a}^{2}
  2. \sf squre \: root \: both \: sides :  \\  \tt\sqrt{ {b}^{2} }   =  \sqrt{ {c}^{2}  -  {a}^{2} }  \\  \tt \: b =  \sqrt{ {c}^{2}  -  {a}^{2} }

\sf step - 2 : sustitute \:the \: value \: of \: c \: and \: a \: then \: simplify

  1. \sf substitute \: the \: given \: value \: of \:  c \: and \: b :  \\  \tt b =  \sqrt{ {15}^{2}  -  {11}^{2} }
  2. \sf simplify \: squres :  \\  \tt b =  \sqrt{225 - 121}
  3. \sf substract :  \\ \tt b =  \sqrt{104}
  4. \sf simplify \: redica l  :  \\  \tt  b =  \sqrt{ {2}^{2} \times 26 }  \\  \tt  \therefore b = 2 \sqrt{26}

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Step-by-step explanation:

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<span>The first three steps of completing the square to solve the quadratic equation x^2 + 4x - 6 = 0, are shown below.

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