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Pani-rosa [81]
3 years ago
8

50 points and brainliest!!!!! fast pls!! (08.02)A pair of equations is shown below. x + y = 5 y = 1/2 x + 2 If the two equations

are graphed, at what point do the lines representing the two equations intersect? A) (2, 5) B)(5, 2) C) (2, 3) D) (3, 2)
Mathematics
1 answer:
likoan [24]3 years ago
5 0
The answer would be C (2,3)
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Which equation has the solution x = 5?
alexgriva [62]
It would be 32-4x=12
32-4(5)=12
32-20=12
12=12
4 0
3 years ago
Read 2 more answers
I NEED HELP IDENTIFYING THE SLOPE PLEASE !!! Pic attatched !!!!
Alexus [3.1K]

Answer:

see explanation

Step-by-step explanation:

Calculate the slope m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = 2,4 ) and (x₂, y₂ ) = (5, 1)

m = \frac{1-4}{5-2}  = \frac{-3}{3} = - 1 ← negative slope

Repeat

with (x₁, y₁ ) = - 7,8) and (x₂, y₂ ) = (- 7, 0)

m = \frac{0-8}{-7+7} = \frac{-8}{0}

Division by zero is undefined, thus slope is undefined.

Repeat with

(x₁, y₁ ) = (6, - 3) and (x₂, y₂ ) = (- 4, - 3)

m = \frac{-3+3}{-4-6} = \frac{0}{-10} = 0 ← zero slope

Repeat with

(x₁, y₁ ) = (3, 5) and (x₂, y₂ ) = (- 1, 2)

m = \frac{2-5}{-1-3} = \frac{-3}{-4} = \frac{3}{4} ← positive slope

7 0
3 years ago
Simplify the expression.<br><br> -2x + -5 + 8x + -4<br><br> Question 3 options:
Leokris [45]

6x + (-9) or 6x - 9

Try looking at the terms for the same things. Such as the variable like X and the negatives add together and make a negative

5 0
3 years ago
2x(squared) + 23x-19=0
Helen [10]
Use quadratic formula

for ax^2+bx+c=0
x=\frac{-b+/- \sqrt{b^2-4ac} }{2a}

given
2x^2+23x-19=0
a=2
b=23
c=-19

x=\frac{-23+/- \sqrt{23^2-4(2)(-19)} }{2(2)}
x=\frac{-23+/- \sqrt{529-152} }{4}
x=\frac{-23+/- \sqrt{377} }{4}

x=\frac{-23+ \sqrt{377} }{4} or \frac{-23- \sqrt{377} }{4}
7 0
4 years ago
Divide using long division.<br><br> <img src="https://tex.z-dn.net/?f=%28x%5E%7B2%7D%20-5%29" id="TexFormula1" title="(x^{2} -5)
Morgarella [4.7K]

Answer:

The quotient = x + 5 and the remainder = 20

Step-by-step explanation:

\frac{x^{2}+0-5 }{x-5}=x+\frac{5x-5}{x-5}

\frac{5x-5}{x-5}=5+\frac{20}{x-5}

The quotient = x + 5 and the remainder = 20

4 0
4 years ago
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