Answer:
The answer to your question is 43.7 g of chocolate
Step-by-step explanation:
Data
56% cocoa
mass of a chocolate bar = 78 g
Process
To solve this problem, use proportions and cross multiplication, consider the mass of the bar is 100%.
78 g of chocolate ------------------- 100%
x ------------------ 56%
x = (56 x 78) / 100
x = 4368/100
x = 43.68 g
-Round to the nearest tenth
Mass of the chocolate = 43.7 g
13 is the answer for ur question
Answer:
2x^3 + 3x - 10
Step-by-step explanation:
Her horizontal distance to the rim satisfies the ratio
(10 ft -6 ft)/distance = tan(25°)
so the distance is
distance = (4 ft)/tan(25°) ≈ 9 ft
Volume is legnth times widht times height
lenght=2x-1
width=x-2
height=x+1
multiply all together
use mass distributive property
distributive=a(b+c)=ab+ac so extending that
(a+c)(c+c)=(a+b)(c)+(a+b)(d) then keep distributing so
(2x-1)(x-2)(x+1)
do each one seperately
do the first two first and put the other one (x+1) to the side for later
(2x-1)(x-2)=(2x-1)(x)+(2x-1)(-2)=(2x^2-x)+(-4x+2)=2x^2-5x+2
then do the other one
(x+1)(2x^2-5x+2)=(x)(2x^2-5x+2)+(1)(2x^2-5x+2)=(2x^3-5x^2+2x)+(2x^2-5x+2)=2x^3-3x^2-3x+2
the lasst form is 2x^3-3x^2-3x+2
