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Mashutka [201]
4 years ago
11

Solve for X under the assumption that X>0 Enter your answer in interval notation using grouping symbols.

Mathematics
1 answer:
irina1246 [14]4 years ago
5 0
There are two answers I found x=9 and x=-5
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Help please time limit...Amanda is choosing between two exercise routines.
Marina86 [1]

Amanda must spend more than 8 minutes on Routine #1 to burn more calories than Routine #2.

Step-by-step explanation:

Routine # 1;

Calories burned in running = 15.5 per minute

Let,

t be the minutes spent running.

T = total calories burned

T = 15.5t

Routine # 2;

Calories burned while walking = 22 calories

Calories burned while running = 12.75 per minute

T = 12.75t + 22

For burning more calories in Routine 1;

Routine 1 > Routine 2

15.5t>12.75t+22\\15.5t-12.75t>22\\2.75t>22\\

Dividing both sides by 2.75

\frac{2.75t}{2.75}>\frac{22}{2.75}\\t>8

Amanda must spend more than 8 minutes on Routine #1 to burn more calories than Routine #2.

Keywords: linear inequality, division

Learn more about division at:

  • brainly.com/question/9136949
  • brainly.com/question/909890

#LearnwithBrainly

7 0
3 years ago
Describe a real-world situation in which you might use the expression 50+2x
zloy xaker [14]
Hope this helps you!

5 0
3 years ago
If ​P(E)=0.55​, ​P(E or ​F)=0.65​, and​ P(E and ​F)=0.20​, find​ P(F).
sleet_krkn [62]

Answer:

.3

Step-by-step explanation:

let x= P(f)

.65= .55+x-.2

P(F)=.3

7 0
3 years ago
A triangle has side lengths of 14, 23, and 27. Is it a right angle ?
shusha [124]

Answer:

No, it is not

Step-by-step explanation:

Here, we want to check if the lenghts given is that of a right angle triangle

For a right angle triangle, the square of the hypotenuse is equal to the sum of the squares of the two other sides

The hypotenuse represents the longest side

So 27^2 = 14^2 + 23^2

The difference between these is 4, and as such the triangle is not a right angled

6 0
3 years ago
Inequalities <br><img src="https://tex.z-dn.net/?f=%20-%205%20%5Ctimes%20%20%2B%202%20%5Cgeqslant%20%20-%2048" id="TexFormula1"
Andrej [43]

\bf -5x+2\geqslant -48\implies -5x \geqslant -50\implies \stackrel{\textit{now, we're dividing by -5}}{\cfrac{-5x}{-5}\stackrel{\stackrel{\downarrow }{\frac{}{}}}{\leqslant}\cfrac{-50}{-5}}\implies x\leqslant 10

5 0
3 years ago
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