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2 years ago

PLZZ HELPPP I need someone to solve these metric system operations!!!

Mathematics

2 answers:

almond37 [142]2 years ago

5 0

1Q279812 128912 98127 128912879

datboythomas123#8606

IS MY DISCORD FRIEND ME!

jk, uhhhhhhhhhhhhhhhhhhhhh... just form it into a question, and ill answer it. K?

aliina [53]2 years ago

5 0

Answer:

Note:Convert all term in needed unit:

10mm=1cm

100cm=1m

1000mg=1g

1000g=1kg

1000ml=1l

999.99g

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Factories A, B and C produce computers. Factory A produces 4 times as manycomputers as factory C, and factory B produces 7 times

Elina [12.6K]

Answer:

The probability is $P(A') = 0.485$

Step-by-step explanation:

Let assume that the number of computer produced by factory C is k = 1

So From the question we are told that

The number produced by factory A is 4k = 4

The number produced by factory B is 7k = 7

The probability of defective computers from A is $P(A) = 0.04$

The probability of defective computers from B is $P(B) = 0.02$

The probability of defective computers from C is $P(C) = 0.03$

Now the probability of factory A producing a defective computer out of the 4 computers produced is

$P(a) = 4 * P(A)$

substituting values

$P(a) = 4 * 0.04$

$P(a) = 0.16$

The probability of factory B producing a defective computer out of the 7 computers produced is

$P(b) = 7 * P(B)$

substituting values

$P(b) = 7 * 0.02$

$P(b) = 0.14$

The probability of factory C producing a defective computer out of the 1 computer produced is

$P(c) = 1 * P(C)$

substituting values

$P(c) = 1 * 0.03$

$P(b) = 0.03$

So the probability that the a computer produced from the three factory will be defective is

$P(t) = P(a) + P(b) + P(c)$

substituting values

$P(t) = 0.16 + 0.14 + 0.03$

$P(t) = 0.33$

Now the probability that the defective computer is produced from factory A is

$P(A') = \frac{P(a)}{P(t)}$

$P(A') = \frac{ 0.16}{0.33}$

$P(A') = 0.485$

3 0

3 years ago

Combining like terms with rational coefficients <br> 7/8m+9/10-2m-3/5

nikklg [1K]

Answer:

Ah yes, one of my favorite topics.

Step 1: Which ever fraction comes first, you will solve it first. For this question, focus on doing $\frac{7}{8}m-2m$ first. Afterwards, do $\frac{9}{10}-\frac{3}{5}$

Step 2: First one equals to 1.125. Next, find the LCD (lowest common dominator, which is 10). $\frac{9}{10} -\frac{6}{10}=\frac{3}{10}$

Step 3: 1.125+3/10

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2 years ago

A rhombus has sides 10 cm long and an angle of 60 degrees. Find the distance between a pair of opposite sides.

natta225 [31]

<span>angle A + angle B = 180 degrees ... rhombus and h is the perpendicular distance between two parallelsides of the rhombus. ... The side length of the rhombus is equal to 10 feet. Find its area. ... A rhombus has 2 congruent opposite acute angles and two congruent ... area of rhombus = 2 (1 / 2) (10 feet) 2 sin (60 degrees)</span>

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2 years ago

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Answer this question:What is the difference between 9 < x and 9 = x? Explain.

maw [93]

9 < x

this means that x is a larger number than 9

9 = x

this means that x is equal to 9

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2 years ago

A line on the wall and a line on the floor are skew. always sometimes never