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2 years ago

Tom has arrive at the time of 259 248s.Find the number of Tom in Day,hour,Minute,Second

Mathematics

1 answer:

Olenka [21]2 years ago

6 0

Answer:

3 days 0 hours 0 minutes 48 seconds

Step-by-step explanation:

Seconds = 259248 s

Number of days = Seconds given / 86400

Where 86400 = seconds in a day

The result is: 3 days remaining 48 seconds

Hours = Seconds Left / 3600 seconds.

Since the seconds left is 48, the hour = 0

Minutes = Seconds Left / 60 seconds.

Since the seconds left is 48, the minute = 0

Result:

3 days 0 hours 0 minutes 48 seconds

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F(x)=x^(2)+3x+4 is this quadratic, linear, or neither

goblinko [34]

Quadratic
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8 0

2 years ago

Solve the system 2x-2y=10 4x-5y=17

stiv31 [10]

Multiply 2x-2y=10 by 2,
4x-4y=20,
given:4x-5y=17
y=3
pluck it in
2x-6=10
move the 6 to the right
2x=16
divide
x=8
y=3

8 0

2 years ago

Read 2 more answers

If each of the following sequences is either arithmetic or geometric, continue the decimal patterns.

I am Lyosha [343]

Answer:

12.8, 11.6, 10.4, 9.2, 8.0, 6.8, 5.6

3, 1.5, 0.75, 0.375, 0.1875, 0.09375, 0.046875

Step-by-step explanation:

The first one is arithmetic as the pattern is deducting 1.2, second one is geometric as it is dividing 2.

4 0

3 years ago

Check all of the ordered pairs that satisfy the equation below.y=2/5x

zvonat [6]

We are going to do this step by step:

Let's start with option A

X = 25 and Y = 5/2

$y=\frac{2}{5}\cdot x=\frac{2}{5}\cdot25=\frac{2\cdot25}{5}=\frac{50}{5}=\frac{5\cdot10}{5\cdot1}=10$

In this case, when X = 25 , then Y = 10 ,which is different to 5/2

X = 14 , Y = 35

$y=\frac{2}{5}\cdot14=\frac{28}{5}$

In case, when X = 14, then Y = 28/5, which is different to 35

X = 40 , Y = 24

$y=\frac{2}{5}\cdot40=\frac{80}{5}=16$

Similarly, in this case, when X = 40, then Y = 16, which is different to 24

X = 10 , Y=4

$y=\frac{2}{5}\cdot10=\frac{20}{5}=4$

Now, in this case, we can see that when X = 10, then Y = 4 which is the same as the given value of Y

X = 50 , Y = 20

$y=\frac{2}{5}\cdot50=\frac{100}{5}=20$

In this case, the values of Y are also the same.

X = 30 , Y = 12

$y=\frac{2}{5}\cdot30=\frac{60}{5}=12$

Again, in this case, the values of Y are the same, so the pair satisfies the equation.

In conclusion: options D, E and F satisfy the equation

3 0

10 months ago

Scientists have discovered a vaccine for a debilitating disease. This year there were 570,000 reported new cases of the disease

Ket [755]

Answer: There are approximately 853827 new cases in 6 years.

Step-by-step explanation:

Since we have given that

Initial population = 570000

Rate at which population decreases is given by

$\frac{2}{3}$

Now,

First year =570000

Second year is given by

$570000\times (\frac{1}{3})$

Third year is given by

$570000(\frac{1}{3})^2$

so, there is common ratio ,

it becomes geometric progression, as there is exponential decline.

so,

$570000,570000\times \frac{1}{3},570000\times( \frac{1}{3})^2,......,570000\times (\frac{1}{3})^6$

a=570000

common ratio is given by

$r=\frac{a_2}{a_1}=\frac{1}{3}$

number of terms = 6

Sum of terms will be given by

$S_n=\frac{a(1-r^n)}{(1-r)}$

We'll put this value in this formula,

$S_6=\frac{570000(1-(\frac{1}{3})^6}{(1-\frac{1}{3})}\\\\=853827.16$

So, there are approximately 853827 new cases in 6 years.

6 0

2 years ago