Part 1: Answer:
(x+1)(x+1)(x-6) = x^3 - 4x^2 - 11x - 6
Step-by-step explanation:
To make r a root, include (x-r) as a factor. (-1+1)(-1+1)(-1-6) is zero even though (-1-6) isn't.
(6+1)(6+1)(6-6) is zero.
Part 2 Answer:
Standard form: y = -x^4 + 12
Degree 4
left end goes down, right end goes down.
Step by step: apply the definitions of standard form, polynomial degree, and "end behavior". In other words, read the textbook.
Part 3: Answer: x = 3, x = 8
Step by step:
x^2-11x = -24
x^2-11x+24 = 0
(x-3)(x-8) = 0
x = 3 or x = 8
Part 4a Answer:
quotient 2x^2 + x - 3
remainder 1
Step by step:
2x^2 + x - 3
___________________
x-4 ) 2x^3 - 7x^2 - 7x + 13
2x^3 - 8x^2
__________
0 + x^2 - 7x + 13
x^2 - 4x
____________
0 - 3x + 13
- 3x + 12
______
1
Part 4b answer:
quotient 2x^2 - 6x + 2
remainder -20
Step by step: you have to know exactly what you are doing. Refer to textbook or Wikipedia.
dividend 2x^3 +14x^2 - 58x
divisor x+10
leading coefficient of divisor must be 1
write coefficients of dividend at top
write coefficients of dividend at left
| 2 14 -58 0
-10 | -20 60 -20
___________
| 2 -6 2 -20
Coefficients of quotient are 2 -6 2
Remainder is -20
quotient = 2x^2 - 6x + 2
Answer:
81 degrees
Step-by-step explanation:
A quadrilateral has four interior angles which sum up to 360 degrees.
As we are given that two angles are right angles which means the sum of two angles will be 180 degrees and the third angle is 99 degrees.
As we know that the four angles sum up to 360 degrees.
Let A,B,C and D denote the four angles,
Then
Sum of angles = 360
A+B+C+D=360
90+90+99+D=360
279+D=360
D=360-279
D= 81 degrees
So the fourth angle is 81 degrees ..
Answer:
145 + 2c = X
Step-by-step explanation:
Fixed cost: 145
PLUS
2 dollars per bumper sticker (c)
After you write this out, you can put this as an actual equation.
Answer:
f^-1(x) = x +6
Step-by-step explanation:
To find the inverse of the function
y = f(x)
solve the equation
x = f(y)
for y.
Here, you want ...
x = f(y)
x = (y -6)
x +6 = y . . . . . . add 6 to both sides
17,000+100+6
I think I hope I'm right
