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sleet_krkn [62]
2 years ago
15

Which inequality is represented by the graph below?

Mathematics
1 answer:
4vir4ik [10]2 years ago
6 0
I don’t no this I’m sorry
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1. What digit is in the tenths place when 12.03 is<br> multiplied by .74?
ioda

Answer:

9

Step-by-step explanation:

12.03 x 0.74=8.9022

the first number after the decimal is the tenths place, the second is the hundreths, the third is the thousandths. Excuse my spelling Im 13.

5 0
3 years ago
Can yall please help lol
const2013 [10]

Answer:

1.) Triangle ABC is congruent to Triangle CDA because of the SAS theorem

2.) Triangle JHG is congruent to Triangle LKH because of the SSS theorem

Step-by-step explanation:

Alright. Let's start with the 1st figure. How do we prove that triangles ABC and CDA (they are named properly) are congruent? First, we can see that segments BC and AD have congruent markings, so that can help us. We also see a parallel marking for those segments as well, meaning that the diagonal AC is also a transversal for those parallel segments. That means we can say that angle CAD is congruent to angle ACB because of the alternate interior angles theorem. Then, the 2 triangles also share the side AC (reflexive property).

So, we have 2 congruent sides and 1 congruent angle for each triangle. And in the way they are listed, this makes the triangles congruent by the SAS theorem since the angle is adjacent to the 2 sides that are congruent.

The second figure is way easier. As you can clearly see by the congruent markings on the diagram, all the sides on one triangle are congruent to the other. So, since there are 3 sides congruent, we can say the triangles JHG and LKH are congruent by the SSS theorem.

4 0
3 years ago
Read 2 more answers
Square OABC is drawn on a centimetre grid. O is (0,0) A is (3,0) B is (3,3) C is (0,3) Write down how many invariant points ther
storchak [24]

Answer:

No invariant point

Step-by-step explanation:

Hello!

When we translate a form, in this case a polygon We must observe the direction of the vector. Since our vector is:

\vec{v}=\left ( \begin{matrix}1\\ 3\end{matrix} \right )

1) Let's apply  that translation to this polygon, a square. Check it below:

2) The invariant points are the points that didn't change after the transformation, simply put the points that haven't changed.

Examining the graph, we can see that no, there is not an  invariant point, after the translation. There is no common point that belongs to OABC and O'A'B'C' simultaneously. All points moved.

3 0
3 years ago
Which statement is true? I know it’s not the first one.
agasfer [191]

Answer:

2nd one: AB = 6

Step-by-step explanation:

Because PQ is 4 (Pythagorean triples), you can prove that triangle PBQ is congruent to PAQ by HL. You can then say AQ is equal to 3 becasue of CPCTC. AQ+QB=AB, or 3+3=6. AB=6

8 0
3 years ago
76 + 4= add the ones and the tens. Do you regroup? yes or no
nikklg [1K]
76 + 4 is 80... don't know what you're asking
6 0
3 years ago
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