Which of the equations below could be the equation of this parabola?

Mathematics

1 answer:

BARSIC [14]3 years ago

7 0

Parabolas like $y=ax^2$ have the y-axis as their symmetry axis, so options B and D are surely wrong.

Moreover, parabolas like $x=ay^2$ have the x-axis as their symmetry axis. If $a>0$ the parabola is concave rightwards, if $a$ the parabola is concave leftwards.

Since your parabola is concave leftwards, the only feasible option is $x=-2y^2$

You might be interested in

What is the median of this data set?

bazaltina [42]

Answer:

Step-by-step explanation:

Because the median is the middle number when the data set is in order least to greatest so you already have it in least to greatest so thank you for helping me.

and for extra just in case.

Mean=16.222

the mean= the average of the data set

Mode is 13,14

The mode is the number that appears the most in a data set and 13 and 14 appear twice.

Your range is=13

Range is the highest number subtracting the lowest number so 24 -11 which =13

Minimum is 11 because the minimum is the lowest number in data set..

Maximum is 24

Maximum is the highest number in the data set.

I hope this helps have a awesome day:)

7 0

3 years ago

Read 2 more answers

Find the consecutive integers even integers whose sum is 264

coldgirl [10]

Name the first even integer you are looking for $x$ . The next even number is $x+2$ .

Their sum is $264$ , so $x+x+2=264$ . That means $2x=262$ , hence $x=131$ .

So, the desired numbers are $131$ and $133$ .