Sum of two angles that are complementary = 90°
<em>m</em>∠1 + <em>m</em>∠2 = 90°
Given :
<em>m</em>∠1 = 12°
Then :-
![12° + ∠2 = 90°](https://tex.z-dn.net/?f=12%C2%B0%20%2B%20%E2%88%A02%20%3D%2090%C2%B0)
![∠2 = 90 - 12](https://tex.z-dn.net/?f=%E2%88%A02%20%3D%2090%20-%2012)
![∠2 = 78°](https://tex.z-dn.net/?f=%E2%88%A02%20%3D%2078%C2%B0)
<h2>∴ <em>m</em>∠2 = 78°</h2>
just think of it like this 6 x (30 - 3) so then it turns into 6 x 27 which is 162 :) I hope this helped :))
Answer:
9
Step-by-step explanation:
use pemdas, or order of operations
Answer:
11+²√10 question
Step-by-step explanation:
11+2 √10x√10÷√10
11+2x10÷√10
31÷√10 is ur answer sir pls mark brainliest
Answer:
the answer is 20
Step-by-step explanation:
20/2= 10. 10-6= 4.