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2 years ago

15

Find the value of X please

1 answer:

vaieri [72.5K]2 years ago

7 0

Answer:

x=2/3

Step-by-step explanation:

6x+6=10

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Find the value of x.

Vika [28.1K]

Answer:

the value of x is 150° because all are 150°

7 0

2 years ago

Henry used his GPS to measure the distances from his house to two locations to the thousandth mile. Then, he rounded both values

patriot [66]

Henri Henri use his GPS to measure the distance from his house to two locations to the thousands of miles then he rounded both values to the nearest hundred which pair of distances could be the nearest actual distances please mark me as brainless I’m really helpful and I did this the answer is 4.32

5 0

2 years ago

Consider the initial value problem y′+5y=⎧⎩⎨⎪⎪0110 if 0≤t<3 if 3≤t<5 if 5≤t<[infinity],y(0)=4. y′+5y={0 if 0≤t<311 i

rosijanka [135]

It looks like the ODE is

$y'+5y=\begin{cases}0&\text{for }0\le t$

with the initial condition of $y(0)=4$ .

Rewrite the right side in terms of the unit step function,

$u(t-c)=\begin{cases}1&\text{for }t\ge c\\0&\text{for }t$

In this case, we have

$\begin{cases}0&\text{for }0\le t$

The Laplace transform of the step function is easy to compute:

$\displaystyle\int_0^\infty u(t-c)e^{-st}\,\mathrm dt=\int_c^\infty e^{-st}\,\mathrm dt=\frac{e^{-cs}}s$

So, taking the Laplace transform of both sides of the ODE, we get

$sY(s)-y(0)+5Y(s)=\dfrac{e^{-3s}-e^{-5s}}s$

Solve for $Y(s)$ :

$(s+5)Y(s)-4=\dfrac{e^{-3s}-e^{-5s}}s\implies Y(s)=\dfrac{e^{-3s}-e^{-5s}}{s(s+5)}+\dfrac4{s+5}$

We can split the first term into partial fractions:

$\dfrac1{s(s+5)}=\dfrac as+\dfrac b{s+5}\implies1=a(s+5)+bs$

If $s=0$ , then $1=5a\implies a=\frac15$ .

If $s=-5$ , then $1=-5b\implies b=-\frac15$ .

$\implies Y(s)=\dfrac{e^{-3s}-e^{-5s}}5\left(\frac1s-\frac1{s+5}\right)+\dfrac4{s+5}$

$\implies Y(s)=\dfrac15\left(\dfrac{e^{-3s}}s-\dfrac{e^{-3s}}{s+5}-\dfrac{e^{-5s}}s+\dfrac{e^{-5s}}{s+5}\right)+\dfrac4{s+5}$

Take the inverse transform of both sides, recalling that

$Y(s)=e^{-cs}F(s)\implies y(t)=u(t-c)f(t-c)$

where $F(s)$ is the Laplace transform of the function $f(t)$ . We have

$F(s)=\dfrac1s\implies f(t)=1$

$F(s)=\dfrac1{s+5}\implies f(t)=e^{-5t}$

We then end up with

$y(t)=\dfrac{u(t-3)(1-e^{-5t})-u(t-5)(1-e^{-5t})}5+5e^{-5t}$

3 0

3 years ago

Pakisagutan lang po help pls

aniked [119]

Answer:

Step-by-step explanation:

S 50 m = 0.050 km

A ∵ 1 m = 100 cm

∴ 5 m = 500 cm

K ∵ 1000 dm = 0.1 km

∴ 1 dm = $\frac{0.1}{1000}$ km

∴ 5246 dm = $\frac{0.1}{1000}\times 5246$ km

= 0.5246 km

P ∵ 1 m = 1000 mm

∴ 5.246 m = 5246 mm

P ∵ 1 hg = 1000 dg

∴ 3.7 hg = 3700 dg

U ∵ 1 g = 100 cg

∴ 0.37 g = 37 cg

E ∵ 1 kg = 1000 g

∴ 370 kg = 370,000 g

8 0

3 years ago

Which is the equation of a libe that has a slope of 1/2 and passes through (2,-3)

skad [1K]

Answer:

Step-by-step explanation:

The equation of a straight line can be represented in the slope-intercept form, y = mx + c

Where c = intercept

Slope, m =change in value of y on the vertical axis / change in value of x on the horizontal axis

change in the value of y = y2 - y1

Change in value of x = x2 -x1

The slope is given as 1/2 and the line passes through (2, - 3)

To determine the intercept, we would substitute x = 2, y = - 3 and m= 1/2 into y = mx + c

y = mx + c. It becomes

- 3 = 1/2 × 2 + c = 1 + c

c = - 3 - 1 = - 4

The equation becomes

y = x/2 - 4

3 0

2 years ago