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Dmitry_Shevchenko [17]

2 years ago

5

Jenna starts her homework at 6:30 P.M. She solves math problems for 20 minutes. She works on a paper for history for 30 minutes

and studies science vocabulary for 15 minutes. Finally, Jenna reads for 40 minutes. When will Jenna finish her homework?

2 answers:

tigry1 [53]2 years ago

5 0

Answer:its either 7:20 or 8:00 i think

Step-by-step explanation:

MatroZZZ [7]2 years ago

4 0

Jenna will finish her homework at 8:15

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Please help in this question. I WILL mark brainliest. NO LINKS

deff fn [24]

Answer:

B, you are correct

Area of the bigger trapezoid = (6 + 2) x 1/2 x 6 = 8 x 1/2 x 6 = 4 x 6 = 24

Area of the smaller trapezoid = (4 + 2) x 1/2 x 3 = 6 x 1/2 x 3 = 3 x 3 = 9

<h2>Area of the shaded area = 24 - 9 = 15</h2>

<em>Hope that helps! :)</em>

<em>Hope that helps! :)</em>

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<em>-Aphrodite</em>

Step-by-step explanation:

6 0

3 years ago

What is the lateral surface area of the square pyramid represented by this net?Enter your answer in the box. ft²A square pyramid

Reika [66]

Answer:

The awnser is 176

Step-by-step explanation:

i have taken the test and got a 90 on it so yea

8 0

2 years ago

Uninhibited growth can be modeled by exponential functions other than A(t) =Upper A 0 e Superscript kt. For example, if an i

laila [671]

The question is incomplete. Here is the complete question.

Uninhibited growth can be modeled by exponential functions other than $A(t)=A_{0}e^{kt}$ . for example, if an initial population P₀ requires n units of time to triple, then the function $P(t)=P_{0}(3)^{\frac{t}{n} }$ models the size of the population at time t. An insect population grows exponentially. Complete the parts a through d below.

a) If the population triples in 30 days, and 50 insects are present initially, write an exponential function of the form $P(t)=P_{0}(3)^{\frac{t}{n} }$ that models the population.

b) What will the population be in 47 days?

c) When wil the population reach 750?

d) Express the model from part (a) in the form $A(t)=A_{0}e^{kt}$ .

Answer: a) $P(t)=50(3)^{\frac{t}{30} }$

b) P(t) = 280 insects

c) t = 74 days

d) $A(t)=50e^{0.037t}$

Step-by-step explanation:

a) n is time necessary to triple the population of insects, i.e., n = 30 and P₀ = 50. So, Exponential equation for growth is

$P(t)=50(3)^{\frac{t}{30} }$

b) In t = 47 days:

$P(t)=50(3)^{\frac{t}{30} }$

$P(47)=50(3)^{\frac{47}{30} }$

$P(47)=50(3)^{1.567}$

P(47) = 280

In 47 days, population of insects will be 280

c) P(t) = 750

$750=50(3)^{\frac{t}{30} }$

$\frac{750}{50}=(3)^{\frac{t}{30} }$

$(3)^{\frac{t}{n} }=15$

Using the property <u>Power</u> <u>Rule</u> of logarithm:

$log(3)^{\frac{t}{30} }=log15$

$\frac{t}{30}log(3)=log15$

$t=\frac{log15}{log3} .30$

t = 74

To reach a population of 750 insects, it will take 74 days

d) To express the population growth into the described form, determine the constant k, using the following:

A(t) = 3A₀ and t = 30

$A(t)=A_{0}e^{kt}$

$3A_{0}=A_{0}e^{30k}$

$3=e^{30k}$

Use Power Rule again:

$ln3=ln(e^{30k})$

$ln3=30k$

$k=\frac{ln3}{30}$

k = 0.037

Equation for exponential growth will be:

$A(t)=50e^{0.037t}$

3 0

2 years ago

What is the sum in simplest form? 5 3/4 + 2 1/2 A) 7 4/6 B) 7 2/3 C) 8 1/4

alina1380 [7]

Answer:

Step-by-step explanation:

5 3/4 + 2 1/2

Add the whole numbers first

5 + 2

Add the fractions next

3/4 + 1/2 = 3/4 + 2/4 = 5/4 = 1 and 1/4

The total is

7 + 1 1/4 = 8 1/4

8 0

2 years ago

Rewrite these in increasing order of length:<br> 133 dm. 433 cm, 308 km, 91 mm

Oksi-84 [34.3K]

$\boxed{91mm$

<h2>Explanation:</h2>

First of all, let's transform each measurement into meter knowing the following relationships:

$1dm=0.1m \\ \\ 1cm=0.01m \\ \\ 1km=1000 m \\ \\ 1mm=0.001m$

Therefore, we can compute the following:

$\bullet \ 133dm \rightarrow 133dm(\frac{0.1m}{1dm})=13.3m \\ \\ \bullet \ 433cm \rightarrow 433cm(\frac{0.01m}{1cm})=4.33m \\ \\ \bullet \ 308km \rightarrow 308km(\frac{1000m}{1km})=308,000m \\ \\ \bullet \ 91mm \rightarrow 91mm(\frac{0.001m}{1mm})=0.091m$

Writing this in increasing order:

$0.091m$

<h2>Learn more:</h2>

jovian planets in order of increasing distance from the Sun: brainly.com/question/12534549

#LearnWithBrainly

7 0

3 years ago