L-s=16
4s-5=l
4s-l=5
3s=21
s=7
l-7=16
l=16+7
l=23
The smaller number is 7 and the greater number is 23
There are two choices to choose from:
a) Grilled chicken
b) Veggie Pizza
36% students voted for veggie pizza. This means the remaining votes will go to the Grilled chicken. Thus grilled chicken received 64% of the student votes.
Since more students voted for the Grilled chicken, it will be on the lunch menu.
Answer:
a = 6/5
b = 7/8
c = 1/5
Step-by-step explanation:
We want to make two of these equations be in terms of the same variable, so let's solve the first and third in terms of b.
5a-24b=-15 -> -3 + 24b/5 = a
48b+35c = 49 -> 49/35 - 48b/35 = 7/5 - 48b/35 = c
Now we can replace the a and c in the second equation and solve for b.
10a+45c=21
10(-3+24b/5)+45(7/5 - 48b/35) = 21
-30 + 48b + 63 - 432b/7 = 21 -> -12 = -96b/7 -> b=7/8
Now we can plug b back into the other two to solve for a and c. I will leave that to you unless you would like the steps there.
a³ + b³ + c³ + 3abc = ( a + b + c)(a² + b² + c² + ab + bc + ca)
if a + b + c = 0. then a³ + b³ + c³ = 3abc
here a + b + c = 15 + (-9) + (-6)
a + b + c = 15 - 15
a + b + c = 0
so a³ + b³ + c³ = 3abc
15³ + (-9)³ + (-6)³ = 3(15)(-9)(-6)
= 2430
so the answer is 2430
Answer:
The required function is:
Step-by-step explanation:
We have to represent the given scenario as an equation or function
Let x be the number of miles driven in a week
Let C(x) be the function of the number of miles driven
As it is given that charges are 150 per week, these charges are constant so they will be used as it is.
It is also given that the cost of car is 0.45 per mile so for x miles the cost will be:
0.45x
Combining both terms, we get
Hence,
The required function is:
