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zhuklara [117]
3 years ago
13

Meaning of anode and cathode​

Physics
1 answer:
MatroZZZ [7]3 years ago
3 0

Answer:

An anode is an electrode through which conventional current (positive charge) flows into the device from the external circuit, while a cathode is an electrode through which conventional current flows out of the device.

Explanation:

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How much force would be required to accelerate a 2kg object at a rate of 15m/ sec?
Anna007 [38]
Im saying a or b but i pick B
5 0
3 years ago
A 140 g baseball is moving horizontally to the right at 35 mis when it is hit by the bat. the ball fl ies off to the le ft at 55
Anit [1.1K]

Answer:

J = 12.32kg*m/s

Explanation:

Assumptions: I'm assuming mis is m/s

Given: The baseball's mass is 140g, so convert to kg, 0.140kg. (Good rule of thumb, in physics convert grams to kilograms). It is initially traveling 35 m/s to the right.

When it hits the bat, it flies left with a velocity of 55 m/s at an angle of 25°. To reiterate:

mass = 0.140kg, Initial: 35m/s, Final: 55m/s at an angle of 25°

For this problem, we have to use the impulse equation, but before that lets break the velocity into components (It will be apparent towards the end):

The initial velocity is moving only in the horizontal direction, so:

v_{0x} = 35 m/s

The final velocity has an x and a y component:

v_{fx} = 55cos(25) = 49.84692829m/s\\v_{fy} = 55sin(25) = 23.2440044m/s

Now the equation for impulse is (dp is Δp, which is difference in momentum; dv is Δv, the difference in velocity; J is impulse):

J = dp= m*dv

To get Δv, we have to find the difference of velocity, that is why we broke it into components. I'm going to define right as positive and left as negative. After that, we find the velocity vector:

dv_{x} = (35-(-49.84692829)) = 84.84692829 m/s\\dv_{y} = (0-(23.2440044)) = -23.2440044 m/s\\dv = \sqrt{(84.84692829)^2+(-23.2440044)^2} = 87.97320604m/s

Finally, substitute into the equation

J = m*dv\\J = 0.140kg * 87.97320604m/s\\J = 12.31624885kg*m/s\\J = 12.32 kg*m/s

J = 12.32kg*m/s

8 0
3 years ago
What is f if you have an object 2.0 m from the concave mirror, and the image is 4.0 m from the mirror?
dezoksy [38]

Answer:

the f is 1.3 m

Explanation:

Given that

An object 2.0m is from the concave mirror

And, the image is 4.0m from the mirror

We need to find out the f

So,

u = -2 m

v = -4 m

1 ÷ f = 1 ÷ v + 1 ÷ u

= (-1 ÷ 4) + (-1 ÷ 2)

= -3 ÷4

f = -4 ÷ 3

= |1.3| m

Hence, the f is 1.3 m

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ololo11 [35]
Tension force transmitted through the chains.
8 0
3 years ago
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A star rotates with a period of 37 days about an axis through its center. The period is the time interval required for a point o
vlabodo [156]

Answer:

T = 1.1285 10⁻² day

Explanation:

For this exercise the forces in the premiere are internal, so the angular momentum is conserved

         L₀ = I₀ w₀

         L  = I w

         L₀ = L

         I₀ w₀ = I w

Angular velocity and period are related

         w₀ = 2π / T₀

         w = 2π  / T

         

The moment of inertia of a sphere is

       I₀ = 2/5 M R²

       I = 2/5 m r²

If we assume that the mass of the star does not change in the transformation

We substitute

         2/5 M R² 2π/T₀ = 2/5 M r² 2π/ T

          R² /T₀ = r² / T

          T = (r / R)² T₀

          T = (6.1 / 2.0 104) 37

          T = 1.1285 10⁻² day

5 0
3 years ago
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